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Blababa [14]
3 years ago
5

Deanna's niece loves to swing at the local playground, so Deanna takes her and pushes her on the swing. Deanna must use (motion

/ transfer / force / energy) to exert a (transfer / motion / force / energy) that causes the swing to change (force / energy / motion / transfer/position).
Physics
1 answer:
Sidana [21]3 years ago
8 0

AnswerShe uses force and air

Explanation:

n bhvygvg gv

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Take the 72 g and divid it by 6 which would equal 12 g each
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What is the name of the force that keeps the planets and other celestial bodies orbiting around the sun
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Gravity is the name of the force that keeps the planets in orbit
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By what factor is the intensity of sound at a rock concert louder than that of a whisper when the two intensity levels are 120 d
77julia77 [94]

Answer:

The intensity of sound at rock concert is  10¹⁰ greater than that of a whisper.

Explanation:

The intensity of sound is given by;

I(dB) = 10Log(\frac{I}{I_o} )

where;

I is the intensity of the sound

I₀ is the threshold of sound intensity = 1 x 10⁻¹² W/m²

The intensity of sound at a rock concert

120 = 10Log(\frac{I}{1*10^{-12}} )\\\\12 = Log(\frac{I}{1*10^{-12}} )\\\\\frac{I}{1*10^{-12}} = 10^{12}\\\\I = 1*10^{-12} *10^{12}\\\\I = 1*10^0\\\\I =1 \ W/m^2

The intensity of sound of a whisper

20 = 10Log(\frac{I}{1*10^{-12}} )\\\\2 = Log(\frac{I}{1*10^{-12}} )\\\\\frac{I}{1*10^{-12}} = 10^{2}\\\\I = 1*10^{-12} *10^{2}\\\\I = 1*10^{-10}\\\\I =10^{-10} \ W/m^2

Thus, the intensity of sound at rock concert is  10¹⁰ greater than that of a whisper.

4 0
3 years ago
Two ice skaters stand at rest in the center of an ice rink. When they push off against one another the 62-kg skater acquires a s
andrew-mc [135]

Answer:

48.22 kg

Explanation:

Applying the law of conservation of momentum,

Total momentum before collision = Total momentum after collision

Note:  Since both skaters were initially at rest, then their total momentum  before collision is equal to zero.

And the velocity of the second skater will be in opposite direction to the first.

0 = mv+m'v'.................... Equation 1

Where m = mass of the first skater, m' = mass of the second skater, v = final velocity of the first skater, v' = final velocity of the second skater.

make v' the subject of the equation

m' = -mv/v'................. Equation 2

Given: m = 62 kg, v = 0.7 m/s, v' = -0.9 m/s (opposite direction to the first)

Substitute into equation 1

m' = -62(0.7)/-0.9

m' = 48.22 kg

5 0
3 years ago
An 80.0 kg skier slides down a hill shaped as shown. Assume
umka21 [38]

The height above the ground from where the skier start is 11.5 m.

<h3>Conservation of energy</h3>

The height above the ground from where the skier start is determined by applying the principle of conservation of energy as shown below;

P.E = K.E

mgh = ¹/₂mv²

gh = ¹/₂v²

h = \frac{v^2}{2g} \\\\h = \frac{15^2}{2 \times 9.8} \\\\h = 11.5 \ m

Thus, the height above the ground from where the skier start is 11.5 m.

Learn more about conservation of energy here: brainly.com/question/166559

8 0
3 years ago
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