Answer:
d. 2m to the right of the pivot
Explanation:
m1 = m
m2 = 0.5m
d1 = 1m
d2 = ?
from principle of moment,
CWM = ACWM
m × 1 = 0.5m × d2
d2 = m/0.5m
= 1/0.5
= 2m
The 2nd child will have to sit 2m to the right
The turning effect of a force is known as the moment. It is the product of the force multiplied by the perpendicular distance from the line of action of the force to the pivot or point where the object will turn.
The principle of moments states that when in
equilibrium the total sum of the anti clockwise
moment is equal to the total sum of the
clockwise moment.
When a system is stable or balance it is said to be in equilibrium as all the forces acting on the system cancel each other out.
In equilibrium
Total Anticlockwise Moment = Total
Total Anticlockwise Moment = TotalClockwise Moment
The magnitude of the current in wire 3 is (I₃)= 0.33A
<h3>How to calculate the value of the magnitude of the current in wire 3 ?</h3>
To calculate the magnitude of the current in wire 3 we are using the Kirchhoff’s current law,
I₁ + I₂ + I₃ = 0
Where we are given,
I₁ = current in wire 1
=0.40 A.
I₂ = current in wire 2
= -0.73 A.
We have to calculate the magnitude of the current in wire 3, I₃
Now we put the known values in above equation, we get,
I₁ + I₂ + I₃ = 0
Or, I₃ = -.(I₁ + I₂)
Or, I₃ = -.(0.40 - 0.73)
Or, I₃ = 0.33 A
From the above calculation, we can conclude that the current in wire 3 is I₃ = 0.33 A
Learn more about current:
brainly.com/question/25537936
#SPJ4
Answer:
23L
Explanation:
Given that:
Initial volume of water = 30mL
Final volume of water after an object was placed on it = 53mL
The volume object added which resulted in a rise to 5mL will be :
Final Volume of object - Initial volume of object
53 mL - 30mL = 23mL
Hence, volume of object added is 23 mL
Ek = (m*V^2) / 2 where m is mass and V is speed, then we can take this equation and manipulate it a little to isolate the speed.
Ek = mv^2 / 2 — multiply both sides by 2
2Ek = mv^2 — divide both sides by m
2Ek / m = V^2 — switch sides
V^2 = 2Ek / m — plug in values
V^2 = 2*30J / 34kg
V^2 = 60J/34kg
V^2 = 1.76 m/s — sqrt of both sides
V = sqrt(1.76)
V = 1.32m/s (roughly)
