Answer:
Yes
Explanation:
Eclipses: Eclipses are also known as game of shadows where one object comes between the star(light source) and another object in a straight line such that the shadow of one object falls on other object. This can occur when the apparent size of the star and the object is almost same.
Talking about the Earth, the geometry is such that the Moon and the Sun are of same apparent size as seen from the Earth. Thus Lunar and Solar eclipse can be seen from the Earth. If we were to go on any other planet the same phenomenon can be seen provided the apparent size of moon and the Sun from that planet is same.
We have seen and recorded many such eclipses on Jupiter. These are from the perspective of Earth. When the moons of Jupiter comes exactly between the Sun and Jupiter the shadow of moon will fall on Jupiter. The places where the shadow falls, one will see a solar eclipse.
Answer:
electrons will migrate untill there is uniform distribution of charge .
and sphere became uniformly charged
Explanation:
as conducting sphere is charged positively it is given . the left side of sphere is charged positively . there is negative charge on the left side that will be attracted by positive charge of right side .
therefore electrons from left side will start migrate towards right side due to attraction of positive charge of right side .
therefore electron will start migrate uniformly .
electrons will migrate untill there is uniform distribution of charge .
and sphere became uniformly charged
The second circuit with 4.5 A current has more resistance.
Explanation:
potential difference= 6 V
resistance of first circuit=0.80 Ω
for second circuit, current= i=4.5 A
using Ohm's law V= i R
6=4.5 R
R=1.33 Ω
So the second circuit has a greater resistance.
I): Speed=Distance/Time
=65-30 km/12:30-12:00 hrs
=35 km/00:30hrs
=3500 m/1800 s
=1.94m/s
ii): Average Speed=Total Distance/Total Time
=100000 m/7200 s
=13.88 m/s
iii):No because it has different speeds at
different time intervals
There are other forces at work here nevertheless we will imagine
it is just a conservation of momentum exercise. Also the given mass of the
astronaut is light astronaut.
The solution for this problem is using the formula: m1V1=m2V2 but
we need to get V1:
V1= (m2/m1) V2
V1= (10/63) 12 = 1.9 m/s will be the final speed of the astronaut after
throwing the tank.
