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lapo4ka [179]
3 years ago
14

Write a statement that explains the relationship among velocity, speed, and direction.

Physics
1 answer:
alexgriva [62]3 years ago
8 0

Answer:

velocity is the speed and direction  of  a moving object

Explanation:

that is basicaly the defention

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Pikes Peak near Denver, Colorado, has an elevation of 14,110 ft. Calculate the pressure at this elevation using three different
kramer

Answer:

a) P = 1240 lb/ft^2

b) P = 1040 lb/ft^2

c) P = 1270 lb/ft^2

Explanation:

Given:

- P_a = 2216.2 lb/ft^2

- β = 0.00357 R/ft

- g = 32.174 ft/s^2

- T_a = 518.7 R

- R = 1716 ft-lb / slug-R

- γ = 0.07647 lb/ft^3

- h = 14,110 ft

Find:

(a) Determine the pressure at this elevation using the standard atmosphere equation.

(b) Determine the pressure assuming the air has a constant specific weight of 0.07647 lb/ft3.

(c) Determine the pressure if the air is assumed to have a constant temperature of 59 oF.

Solution:

- The standard atmospheric equation is expressed as:

                           P = P_a* ( 1 - βh/T_a)^(g / R*β)

                          (g / R*β) = 32.174 / 1716*0.0035 = 5.252

                            P = 2116.2*(1 - 0.0035*14,110/518.7)^5.252

                            P = 1240 lb/ft^2

- The air density method which is expressed as:

                            P = P_a - γ*h

                            P = 2116.2 - 0.07647*14,110

                            P = 1040 lb/ft^2

- Using constant temperature ideal gas approximation:

                            P = P_a* e^ ( -g*h / R*T_a )

                            P = 2116.2* e^ ( -32.174*14110 / 1716*518.7 )

                            P = 1270 lb/ft^2

6 0
3 years ago
Read 2 more answers
1. Calcular la masa de mercurio que pasó de 30 °C hasta 120 °C y absorbió 4400 cal. Calor específico del
timofeeve [1]

Answer:

Masa, m = 0.088 kg

Explanation:

Given the following data;

Temperatura inicial = 30°C

Temperatura final = 120°C

Capacidad calorífica específica = 138J/kg.K

Calor absorbido, Q = 4400 cal.

Para encontrar la masa;

La capacidad calorífica viene dada por la fórmula;

Q = mct

Dónde;

Q representa la capacidad calorífica o la cantidad de calor.

m representa la masa de un objeto.

c representa la capacidad calorífica específica del agua.

dt representa el cambio de temperatura.

dt = T2 - T1

dt = 120 - 30

dt = 90°C to kelvin = 273 + 90 = 363K

Sustituyendo en la fórmula, tenemos;

4400 = m*138*363

4400 = 50094m

m = \frac {4400}{50094}

Masa, m = 0.088 kg

7 0
3 years ago
When placed near another charge, a 20 microcoulomb charge experiences an attractive force of 0.080 N. What is the electric field
prohojiy [21]

Answer:

E = 4000 N/C

Explanation:

Given the following data;

Force = 0.080 N.

Charge, q = 20 microcoulomb = 20 * 10^-6 = 2 * 10^-5 Coulombs

To find the electric field strength;

Mathematically, the electric field strength is given by the formula;

Electric field strength = force/charge

Substituting into the formula, we have;

E = 0.080/0.00002

E = 4000 N/C

8 0
3 years ago
A 20Kg box is pushed across the floor at a constant velocity with a force of 200N. What is the
Shkiper50 [21]

Answer:

The kinetic coefficient of friction between the box and the floor is 1.020.

Explanation:

Let suppose that box is on horizontal ground. According to the Newton's Laws, an object has a net acceleration of zero when either is at rest or moves at constant velocity. Friction is a reaction to the external force that moves the box. Hence, the equation of equilibrium for the 20-Kg box is:

\Sigma F = F-f = 0 (Eq. 1)

Where:

F - External force, measured in newtons.

f - Friction force, measured in newtons.

If we know that F = 200\,N, then the magnitude of the kinetic friction force is:

f = F

f = 200\,N

In addition, friction force is represented by the following formula:

f = \mu_{k}\cdot m\cdot g (Eq. 2)

Where:

\mu_{k} - Kinetic coefficient of friction, dimensionless.

m - Mass, measured in kilograms.

g - Gravitational acceleration, measured in meters per square second.

Now we clear the kinetic coefficient of friction:

\mu_{k} = \frac{f}{m\cdot g}

If we know that f = 200\,N, m = 20\,kg and g = 9.807\,\frac{m}{s^{2}}, then the kinetic coefficient of friction is:

\mu_{k} = \frac{200\,N}{(20\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)}

\mu_{k} = 1.020

The kinetic coefficient of friction between the box and the floor is 1.020.

4 0
3 years ago
Will someone please look at my other questions
Yuliya22 [10]

Answer:

eeeeeeeeeeeeeeeeeeeeeeeeeeeee

Explanation:

5 0
4 years ago
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