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Montano1993 [528]
3 years ago
6

A-line passes through the points (2, -2) and (-6,2). the point (a,-4) is also in the line. what is the value of A

Mathematics
2 answers:
Tomtit [17]3 years ago
8 0
I believe the answer would be d.6
zepelin [54]3 years ago
6 0

Answer:

d 6  

it is not A B or c its

Step-by-step explanation:

edge 2020

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Determine whether the polynomial is a difference of squares and if it is, factor it.
patriot [66]
(y-14)(y+14). You just square root 196

3 0
3 years ago
A snowball has a radius of 7cm. What is the volume of the snowball?
BabaBlast [244]

Answer:

The volume is 1436.8in^2 .

Step-by-step explanation:

-To find the volume of a sphere, you need the formula:

V = \frac{4}{3} \pi r^3

-Use the radius for the formula:

V = \frac{4}{3} \pi 7^3

-Then, you solve:

V = \frac{4}{3} \pi 7^3

V = \frac{4}{3} × \pi × 7^3

V = \frac{4}{3} \pi × 343

V = \frac{1372}{3} \pi = 1436.755

-Round the answer to the nearest tenth:

V = 1436.8

So, therefore the volume is 1436.8in^2 .

7 0
3 years ago
Can someone help me
Vesna [10]

TURTLES AREN'T GREEN?!?!?!?

3 0
3 years ago
The daily demand for ice cream cones at a price of $1.20 per cone is 50 cones. At a price of $2.20 per cone, the demand is 30 co
Lapatulllka [165]

Answer:

<h2>The demand at a price of $1.50 per cone is 44 cones</h2>

Step-by-step explanation:

 let us apply the interpolation formula to solve this problem

we have

\frac{y-y1}{x-x1} =\frac{y2-y1}{x2-x1}

Now let us set the values to the notation above

x= $1.20

x1= $2.20

x2= $1.50

y = 50 cones

y1= 30 cones

y2= ?

y2= \frac{(y-y1)}{(x-x1)} (x2-x1)+y1

Substituting our given data we have

y2= \frac{(50-30)}{(1.2-2.2)} (1.5-2.2)+30\\\\y2=  \frac{20}{-1} (-0.7)+30\\\\y2=   (20*0.7)+30\\y2= 14+30\\y2= 44

the demand at a price of $1.50 per cone is 44 cones

4 0
3 years ago
A basketball player makes 70% of his free throws the random numbers below represent 20 trials for a simulation let the numbers 0
Nesterboy [21]

Answer:

40%

Step-by-step explanation:

Given the result of the simulation below:

(5,5) (0,6) (9,6) (7,4) (9,1) (7,3) (0,4) (9,3) (2,9) (1,4)

(6,8) (5,3) (1,7) (1,7) (1,8) (3,5) (7,2) (2,1) (0,6) (1,8)

n(S)=20

  • The numbers 0 to 6 represent a made free throw .
  • The numbers 7 to 9 represent a missed free throw.
  • Therefore, any result containing 7 to 9 does not satisfy our requirement that the player makes both throws.

Let Event A be the event that the player made both throws

The pairs in which the player made both throws are:

(5,5) (0,6) (0,4) (1,4) (5,3)  (3,5)  (2,1) (0,6)

n(A)=8

Therefore:

P(A)=\frac{n(A)}{n(S)}=\frac{8}{20}=0.4\\

The probability that the player made both throws is 40%.

6 0
3 years ago
Read 2 more answers
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