You have two 30-60-90 triangles, ADC and BDC.
The ratio of the lengths of the sides of a 30-60-90 triangle is
short leg : long leg : hypotenuse
1 : sqrt(3) : 2
Using triangle ADC, we can find length AC.
Using triangle BDC, we can find length BC.
Then AB = AC - BC
First, we find length AC.
Look at triangle ACD.
DC is the short leg opposite the 30-deg angle.
DC = 10sqrt(3)
AC = sqrt(3) * 10sqrt(3) = 3 * 10 = 30
Now, we find length BC.
Look at triangle BCD.
For triangle BCD, the long leg is DC and the short leg is BC.
BC = 10sqrt(3)/sqrt(3) = 10
AB = AC - BC = 30 - 10 = 20
Let x = cups of 11% wheat, and y = cups of 63% wheat
He wants 12 cups in total, so we need:
x + y = 12
These 12 cups need to have 50% wheat, which means we are looking at 12*.5 = 6 cups of wheat in total, so our second equation is:
.11x + .63y = 6
We have two equations and two variables. So we can solve by using any means you want. I used substitution:
x = 12 - y
.11(12-y) + .63y = 6
1.32 -.11y + .63y = 6
.52y = 4.68
y = 9
Which means x = 3
Thus, 3 cups of 11% and 9 cups of 63%.
Since the slope of f(x) is 4 (from 4x) and the slope of g(x) is 7, that means that f(x) changes 4 every time x changes, but g(x) changes 7, making g(x) more steep and f(x) less steep
<span>An eagle is said to fly a total of 290 miles in 5 days
We need to find how far did the eagle fly per day if it flies the same
distance.
=> We need to divide the total distance in 5 in order to get the answer
=> 290 / 5
=> 58
Therefore, an eagle fly 58 miles per day and able to reach the total of 290 miles in 5 days.
First day 58
2nd day = 116 miles
3rd day = 174 miles
4th day = 232 miles
5th day = 290 miles
</span>
Answer:
owo
Step-by-step explanation:
