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2 years ago

13

PLZ ANSWER !!! QUICKLY

1 answer:

a_sh-v [17]2 years ago

4 0

The answer is 560in^3

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Need some math help!!

BlackZzzverrR [31]

It's the second one.

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2 years ago

You need to buy 5 notebooks for your classes at school.Each notebook costs $2.79. What is the total cost before tax?

lesya692 [45]

Answer:

$13.95

Step-by-step explanation:

You need to multiply the 5 notebooks with the costs of each notebook, which gives you the total costs before tax.

7 0

2 years ago

HELPP!!what is the answer to this picture above^

nasty-shy [4]

Answer:

$\fbox{ \fbox { \sf{Distance = \sf{15 \: units}}}}$

${ \fbox { \fbox { \sf{Midpoint = { \sf{ \: (12 \: , \: 10.5)}}}}}}$

Step-by-step explanation:

$\star{ \: \sf { \: Let \: the \: points \: be \: A \: and \: B}}$

$\star { \sf{Let \: A(6 \:, 6) \: be \: (x1 ,\: y1) \: and \: B(18 ,\: 15) \: be \: (x2 \:, y2)}}$

$\underline{ \underline{ \tt{Finding \: the \: distance}}}$

$\boxed{ \sf{Distance = \sqrt{ {(x2 - x1)}^{2} + {(y2 - y1)}^{2} } }}$

$\mapsto{ \sf{Distance = \sqrt{ {(18 - 6)}^{2} + {(15 - 6)}^{2} } }}$

$\mapsto{ \sf{Distance = \sqrt{ {(12)}^{2} + {(9)}^{2} } }}$

$\mapsto{ \sf{Distance = \sqrt{144 + 81}}}$

$\mapsto{ \sf{Distance = \sqrt{225} }}$

$\mapsto{ \sf{Distance = \sqrt{ {15}^{2} } }}$

$\mapsto{ \boxed{\sf{Distance = 15 \: units}}}$

$\underline{ \underline {\tt{Finding \: the \: Midpoint}}}$

$\boxed{ \sf{Midpoint = ( \frac{x1 + x2}{2} \: , \: \frac{y1 + y2}{2} )}}$

$\mapsto{ \sf{Midpoint = ( \frac{6 + 18}{2} \: , \: \frac{6 + 15}{2} )}}$

$\mapsto{ \sf{Midpoint = ( \frac{24}{2} \: , \: \frac{21}{2} )}}$

$\mapsto{ \boxed{ \sf{Midpoint = (12 \: , \: 10.5)}}}$

Hope I helped!

Best regards! :D

~ $\sf{TheAnimeGirl}$

3 0

2 years ago

Help me please help pleaseeeeeeeeeeeee

LenaWriter [7]

Answer:

(8,3)

Step-by-step explanation:

Point c is seven units away from the line x = 1

So we move seven units to the right of the line x = 1

the x value = 8

y value = 3

Coordinates = (8,3)

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

3 0

2 years ago

If the beginning temperature was -13 at 5:00 a.m

Neporo4naja [7]

Answer:

what the question in this

Step-by-step explanation:

5 0

2 years ago