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Evaluate the expression for y = -7.<br><br> 2y = __

vivado [14]

Answer:

2y=-14

Step-by-step explanation:

If y=-7 and you multiply y by 2, you do the same thing to both sides and get -7 × 2 = -14

5 0

3 years ago

How do graphs and equations reveal information about a relationship between two quantities

fiasKO [112]

Graph and equation both shows the proportional comparison between two quantities

for example, equation y = 4x, this means, the value of 'y' will always be 4 times the value of 'x'

More complex equation such as y = 3x + 5, means that the value of 'y' equals to 5 more triples of value of 'x'

Another example is the conversion graph attached below, it shows the relationship between kilometers and miles. For example, we want to find out how many miles are in 10 kilometers, we would draw a line from the point that shows 10 km towards the graph, then across from the graph to miles, and we'd get a reading of 12 miles.

3 0

4 years ago

Hurry please will give brainlest will follow like and thank and give points please hurry and help.

Molodets [167]

-2y-11=Z

n/4 -5=m

.................

7 0

4 years ago

A store sells 12 cans of soup for $7.50 How much would it cost to purchase 6 cans of soup?<br>

ra1l [238]

Per can cost 0.625 so if you multiply that by 6 you’ll get $3.75 as the total cost for the 6 cans.

6 0

3 years ago

In an orienteering class, you have the goal of moving as far (straight-line distance) from base camp as possible by making three

RUDIKE [14]

Answer:

The greatest distance we can be from the base camp at the end of the third displacement is 6.69 km

Step-by-step explanation:

We can think of each displacement as a vector, with a given magnitude and direction.

A vector can be written using its x and y coordinates like this

$\vec{t}=(x, y)$

So, for the displacements a and c their vector coordinates would be:

$\vec{a}=(2, 0)$

$\vec{c}=(-1, 0)$

As the b displacement has an angle of 30° toward the north from due east, we can find its x and y coordinates using the following formulas:

$x=(magnitude)*cos(angle)$

$y=(magnitude)*sin(angle)$

Note: the angle in the formula is the one formed with the east measured counterclockwise.

So, the x and y coordinates for the b displacement will be:

$\vec{b}=(2*cos(30), 2*sin(30))$

As the vector additon is commutative, the order won't affect the final position. Nevertheless, any change in the direction of any displacement will change the final position. So, in order to find the combination greatest distance we should calculate the following additions and find the one with the greatest magnitude:

$\vec{R_{1}} =\vec{a}+\vec{b}+\vec{c}$

$\vec{R_{2}} =\vec{a}-\vec{b}+\vec{c}$

$\vec{R_{3}} =\vec{a}+\vec{b}-\vec{c}$

$\vec{R_{4}} =\vec{a}-\vec{b}-\vec{c}$

Each resultant vector can be found adding each component. Afterwards, the magnitude can be found using the following formula:

$|\vec{R}|=\sqrt[ ]{(R_{x})^2 +{(R_{y})^2}}$

Now, let's calculate!

$\vec{R_{1}} =\vec{a}+\vec{b}+\vec{c}$

$R_{1_x}} =2+2*cos(30)-1=2.73$

$R_{1_y}} =0+2*sin(30)+0=1$

$\vec{R_{1}}=(2.73,1)$

$|\vec{R_{1}}|=\sqrt[ ]{(2.73)^2 +{(1)^2}}=3.86$

$\vec{R_{2}} =\vec{a}-\vec{b}+\vec{c}$

$R_{2_x}} =2-2*cos(30)-1=0.73$

$R_{2_y}} =0-2*sin(30)+0=-1$

$\vec{R_{2}}=(-0.73,-1)$ }

$|\vec{R_{2}}|=\sqrt[ ]{(-0.73)^2 +{(-1)^2}}=1.03$

$\vec{R_{3}} =\vec{a}+\vec{b}-\vec{c}$

$R_{3_x}} =2+2*cos(30)+1=4.73$

$R_{3_y}} =0+2*sin(30)-0=1$

$\vec{R_{3}}=(4.73,1)$

$|\vec{R_{3}}|=\sqrt[ ]{(4.73)^2 +{(1)^2}}=6.69$

$\vec{R_{4}} =\vec{a}-\vec{b}-\vec{c}$

$R_{4_x}} =2-2*cos(30)+1=1.26$

$R_{4_y}} =0-2*sin(30)-0=1$

$\vec{R_{4}}=(1.26,-1)$

$|\vec{R_{4}}|=\sqrt[ ]{(1.26)^2 +{(-1)^2}}=1.79$

So, after all the calculation, we can know for sure that the vector $\vec{R_{3}}$ has the biggest magnitude. Then, the greatest distance we can be from the base camp at the end of the third displacement is 6.69 km

7 0

3 years ago