Answer:
Time t = 2 seconds
It will reach the maximum height after 2 seconds
Completed question;
Amir stands on a balcony and throws a ball to his dog who is at ground level. The ball's height, in meters above the ground, after t seconds that Amir has thrown the ball is given by:
H (t) = -(t-2)^2+9
many seconds after being thrown will the ball reach its maximum height?
Step-by-step explanation:
The equation of the height!
h(t) = -(t-2)^2 + 9 = -(t^2 -4t +4) + 9
h(t) = -t^2 +4t -4+9
h(t) = -t^2 + 4t +5
The maximum height is at dh/dt = 0
dh/dt = -2t +4 = 0
2t = 4
t = 4/2 = 2
Time t = 2 seconds
It will reach the maximum height after 2 seconds
Use the substitution method for y=0
(40,0)
y=0
0=0
Answer: (40,0) It does make the equation y=0 true
The numerator is 0, the denominator is -11, the division symbol is -, and the value of the fraction is 0 because the value of the numerator is 0
Answer:
x=t-p
Step-by-step explanation:
just move p to the other side and since it crosses the equals sign so you have to change it from positive to negative
Answer:
The answer is 15
Step-by-step explanation:
50% of 30
30 × 50 ÷ 100 = 1500/100 = 15
Thus, The answer is 15
<u>-TheUnknownScientist</u><u> 72</u>
