Answer:
11. Volume = 2181.2mm^3
12. Surface Area = 1204.49mm^2
Step-by-step explanation:
We first need to find the hypotenuse side of the triangle using the Pythagorean theorem:
a^2+b^2 = c^2
13.3^2+20.5^2 = c^2
176.89+420.25 = c^2
597.14 = c^2
24.44 = c
Now we can find the volume using the formula:
V = 1/4(16)sqrt-13.3^4+2(13.3*20.5)^2+2(13.3*24.44)^2
-20.5^4+2(20.5*24.44)^2-24.44^4
V = 2181.2mm^3
To find the surface area using the surface area formula:
A = (13.3*16)+(20.5*16)+(24.44*16)+1/2sqrt
13.3^4+2(13.3*20.5)^2+2(13.3*24.44)^2
-20.5^4+2(20.5*24.44)^2-24.44^4
A = 1204.49mm^2
If you mean 756.04, the answer is 756.0. 4 is closer to 0.
5 Or More, raise the score
4 Or Less, let it rest
Answer:
Step-by-step explanation:
A system of linear equations is one which may be written in the form
a11x1 + a12x2 + · · · + a1nxn = b1 (1)
a21x1 + a22x2 + · · · + a2nxn = b2 (2)
.
am1x1 + am2x2 + · · · + amnxn = bm (m)
Here, all of the coefficients aij and all of the right hand sides bi are assumed to be known constants. All of the
xi
’s are assumed to be unknowns, that we are to solve for. Note that every left hand side is a sum of terms of
the form constant × x
Solving Linear Systems of Equations
We now introduce, by way of several examples, the systematic procedure for solving systems of linear
equations.
Here is a system of three equations in three unknowns.
x1+ x2 + x3 = 4 (1)
x1+ 2x2 + 3x3 = 9 (2)
2x1+ 3x2 + x3 = 7 (3)
We can reduce the system down to two equations in two unknowns by using the first equation to solve for x1
in terms of x2 and x3
x1 = 4 − x2 − x3 (1’)
1
and substituting this solution into the remaining two equations
(2) (4 − x2 − x3) + 2x2+3x3 = 9 =⇒ x2+2x3 = 5
(3) 2(4 − x2 − x3) + 3x2+ x3 = 7 =⇒ x2− x3 = −1
x=8 ggggggggggggggggggggggggggggggggggg
Answer:
4
Step-by-step explanation:
square root of 25 is 5
9 decreased by 5 is 9-5=4
