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sattari [20]
3 years ago
15

The mass per unit volume of a substance is called __________.

Mathematics
1 answer:
astraxan [27]3 years ago
3 0

Answer: Density

This measurement tells you how packed in a substance is. The higher the density, the more the object weighs for a certain volumetric unit (such as a cubic meter). Eg: a cubic meter of feathers is likely to weigh less than a cubic meter of solid gold because the feathers have a lot more air in them as opposed to the gold which is more compact.

density = mass/volume is the formula you often use

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Explaining Graphs of Functions
yKpoI14uk [10]

Answer:

please, check the explanation.

Step-by-step explanation:

Hello, I can help you with this

using the graph of a function you can find the value of f (x), all you need to do is locate on the x axis, the value, in this case 3, and we will find f (3), locate the number (3 ) on the x-axis and see what is the value of y that the function takes at that point, that will be the value f (3)

I hope it helps , Have a nice day

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3 years ago
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53/11 as a decimal please help
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Answer:

i think that the answer is 4.8181818

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3/4 - 1/2n =5/8. solve for n
maks197457 [2]
-22/8, simplified would be -11/4
6 0
3 years ago
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A. Complete the chart based on the initial conditions:
Nata [24]

Answer:

a.

Month\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ Pop(whole \ ant)\\month1 => x_1=80\times0.94^1=1128\\month2=>x_2=1200\times0.94^2=1060\\month3=>x_3=1200\times0.94^3=996\\month4=>x_4=1200\times0.94^4=936

b.

week Number\ \ \ \ \ \ \ \ \ \ \ \ \ \ Mass(g)\\week1 => x_1=80\times1.1^1=88g\\week2=>x_2=80\times1.1^2=96.8g\\week3=>x_3=80\times1.1^3=106.48g\\week4=>x_4=80\times1.1^4=117.128g

Step-by-step explanation:

a. From the information provided, we can deduce that the population death's follows a Geometric sequence in the form (a,ar,ar^2,ar^3...) where a-first \ term and r-common \ ratio

#Since the population is reducing, r can is obtained as r=1-r=0.94

#The n^t^h term is obtained using the formula x_n=ar^(^n^-^1^), given a=1200

The number of ants alive after every month (in first 4 months)

Month\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ Pop(whole \ ant)\\month1 => x_1=80\times0.94^1=1128\\month2=>x_2=1200\times0.94^2=1060\\month3=>x_3=1200\times0.94^3=996\\month4=>x_4=1200\times0.94^4=936

The ant's alive after 4 months is obtained as the value of x_5

x_n=ar^(^n^-^1^)\\1-x_5=1-1200\times 0.94^4=936.89\\\approx 936

Hence, 936 ants are alive after 4 months.

b. As with the above question, the kitten population follows a geometric sequence: (a,ar,ar^2,ar^3...).

#Since it's a growing population , the common ration is the sum of 100% + the growth rate,

r=1.1 and a=80 and x_n=ar^(^n^-^1^)

The population after 4weeks will be:

week Number\ \ \ \ \ \ \ \ \ \ \ \ \ \ Mass(g)\\week1 => x_1=80\times1.1^1=88g\\week2=>x_2=80\times1.1^2=96.8g\\week3=>x_3=80\times1.1^3=106.48g\\week4=>x_4=80\times1.1^4=117.128g

8 0
3 years ago
What is the length of AB?
makkiz [27]
The radius of the circle is given to be r = 14.5

Let the center be O. So OB is the radius = 14.5

We can draw a triangle as shown in the image below. We have a right angled triangle. We know the hypotenuse and the base, we need to find the perpendicular side. This can be done using the Pythagorean theorem.

So, we can write:

(14.5)^{2}=10^{2}+OA^{2} \\  \\ 
OA^{2}=110.25 \\  \\ 
OA=10.5

Thus, the measure of OA = 10.5

OB = OA + AB

14.5 = 10.5 + AB
⇒
AB = 4
3 0
3 years ago
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