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Anarel [89]
3 years ago
11

Solve x^2-8x=3 by completing the square.

Mathematics
1 answer:
vfiekz [6]3 years ago
7 0

Answer:

x=4+(19)^1/2,x=4-(19)^1/2

Step-by-step explanation:

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3х – 8y = 34<br> 7х + 4у = -34<br> Solve by elimination <br> Y and x<br> Please show steps ):
garri49 [273]

Answer:

The answer would be (-2, -5)

Step-by-step explanation:

3x - 8y= 34

2(7x + 4y = -34)

3x - 8y=34

14x + 8y= -68

----------------------

     17x= -34    divided by 17

       x = -2

3(-2) -8y= 34

-6 -8y =34 add 6

   -8y= 40  divide by -8

      y = -5

if you want to check the answer replacing -2 for x and -5 for y

7(-2) + 4(-5)= -34

-14 + (-20) = -34

-34 = -34

I hope this help sorry I'm not good explaining

4 0
2 years ago
Brandon mows the neighbor's yard to earn extra
olganol [36]

Answer:

7 is the answer you're looking for

5 0
2 years ago
Each egg carton holds one dozen eggs. Michael's chicken farm fills 121 egg cartons. He thinks that there were over 1500 eggs. Is
Kobotan [32]
121 x 12 = 1452 so over 1500 is not a correct estimate. Less than 1500 is the right estimate
3 0
2 years ago
A purchaser of electric relays buys from two suppliers, A and B. Supplier A supplies two of every three relays used by the compa
inessss [21]

Answer:

The probability that at most 38 of the 60 relays are from supplier A is P(X≤38)=0.3409.

Step-by-step explanation:

We can model this question with a binomial distribution random variable.

The sample size is n=60.

The probability that the relay come from supplier A is p=2/3 for any relay.

If we use a normal aproximation, we have the mean and standard deviation:

\mu=np=60*(2/3)=40\\\\\sigma=\sqrt{npq}=\sqrt{60*(2/3)*(1/3)} =3.65

The probability that at most 38 of the 60 relays are from supplier A is P(X≤38)=0.3409:

P(X\leq38)=P(X

5 0
2 years ago
need help ASAP plz
ruslelena [56]
First shape: no parallel nor perpendicular

Second shape: parallel sides

Third shape: parallel sides

Fourth shape: perpendicular sides

Fifth: perpendicular sides

Hope this helps!! Have a nice day!!
8 0
2 years ago
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