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ikadub [295]
3 years ago
11

Which set of transformations would prove ALMN - APQR?

Mathematics
2 answers:
Gnoma [55]3 years ago
6 0

Answer:

2 I think

Step-by-step explanation:

Levart [38]3 years ago
5 0

Answer:

D. Translate ΔPQR by the rule (x + 1, y − 1), and dilate ΔP′Q′R′ by a scale factor of 2 from point R.

Step-by-step explanation:

I got it correct on the quiz, so you should to. Trust Me.

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Ralph needs 6 cups of milk to make a chocolate shake for his family. His measuring device measures liquids by the pint. If 1 pin
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Ralph will have to measure 3 pints
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The length of a rectangular field is 75 yards. This is 3 yards more than twice the width. How wide is the field?
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length=75yd\\\\width=w\\\\2w+3=75\ \ \ \ \ \ |subtract\ 3\ from\ both\ sides\\\\2w=72\ \ \ \ \ \ |divide\ both\ sides\ by\ 2\\\\\boxed{w=36\ (yd)}
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3 years ago
True or false: the mayans wrote the digits in their numerals in a vertical format
svetlana [45]

Answer:

True

Step-by-step explanation:

6 0
3 years ago
The following probabilities are based on data collected from U.S. adults. Individuals are placed into a weight category based on
sweet-ann [11.9K]

Answer:

the probability that a randomly selected U.S. adult weighs less than the overweight(but not obese) is 0.394

Step-by-step explanation:

  Given the data in the question;

                Underweight   Healthy Weight    Overweight (not Obese)    Obese

Probability       0.017              0.377                        0.343                          0.263

so

P( underweight) = 0.017

P( Healthy Weight) = 0.377

P( Overweight (not Obese) ) = 0.343

P( Obese ) = 0.263

now, the probability that a randomly selected U.S. adult weighs less than the overweight(but not obese) range will be;

P( weigh less than overweight(but not obese) =  P( underweight) + P( Healthy Weight)

P( weigh less than overweight(but not obese) = 0.017 +  0.377

P( weigh less than overweight(but not obese) = 0.394

Therefore, the probability that a randomly selected U.S. adult weighs less than the overweight(but not obese) is 0.394

6 0
3 years ago
Lincoln Middle School had a canned food drive. The 6th graders brought in 5.75 boxes of canned food, the 7th graders brought in
makkiz [27]

Answer:

The total number of boxes of canned food brought in by the three grades is 17.63 boxes

Step-by-step explanation:

To find the total number of canned foods brought in by the three grades, we will have to add the number of canned foods brought by each of the grades to each other. Careful attention has to be paid to the decimal points.

Canned foods brought by 6th graders: 5.75 boxes

Canned foods brought by 7th graders: 6.5 boxes

Canned foods brought by 6th graders: 7/1.3 boxes

We may have a slight challenge adding in 7/1.3 boxes to the other figures. What we can do now is to evaluate it to a decimal value by dividing it up.

7/ 1.3 will be the same thing as 7 divided by 1.3 = 5.38 boxes.

hence, we have 5.75 +6.5+ 5.38= 17.63 boxes

The total number of boxes of canned food brought in by the three grades is 17.63 boxes

3 0
3 years ago
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