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kiruha [24]
3 years ago
8

Products is a manufacturer of large flower pots for urban settings. The company has these​ standards: LOADING...​(Click the icon

to view the​ standards.) Requirements 1. Compute the standard cost of each of the following inputs per​ pot: direct​ materials, direct​ labor, variable manufacturing​ overhead, and fixed manufacturing overhead. 2. Determine the standard cost of one flower pot. Requirement 1. Compute the standard cost of each of the following inputs per​ pot: direct​ materials, direct​ labor, variable manufacturing​ overhead, and fixed manufacturing overhead. ​(Round your answers to the nearest​ cent.) ▼ x = Standard cost of input

Business
1 answer:
nadezda [96]3 years ago
7 0

Answer and Explanation:

The computation is shown below:

1. The standard cost for each one is as follows

For Direct materials, it is

= 9.6 pounds × $4.55 Per pound

= $43.68

For Direct labour, it is  

= 1 hour × $15.80 per hour

= $15.8

For Variable manufacturing overhead, it is

= 1 hour × $3.40 per hour

= $3.40

For Fixed Manufacturing overhead, it is

= 1 hour × $6 per hour

= $6

2. The standard cost of one flower pot is shown below:

= $43.68 + $15.80 + $3.40 + $6

= $68.88

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Answer:

Reduction in work in progress = $7500

Explanation:

given data

time = 10 hours

time = 15 hours

worth  = $1,500

to find out

reduction in work in process value

solution

we find work in progress   by this formula

work in progress  = Flow rate  × Cycle Time     .......................1

so Initial work in progress is

Initial work in progress   = (1 per hour)  × 10 hours = 10

and Final work in progress is here

Final work in progress   = (1 per hour) × 15 hours = 15

so

Initial work in progress   value = 10  × 1500

Initial work in progress   value= $15000

and

Final work in progress    value =15  × 1500

Final work in progress    value = $22500

so

Reduction in work in progress = $22500 - $15000

Reduction in work in progress = $7500

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On January 1, an investment account is worth 50,000. On May 1, the value has increased to 52,000 and 8,000 of new principal is d
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The question is incomplete. The complete question is :

On January 1, an investment account is worth 50,000. On May 1, the value has increased to 52,000 and 8,000 of new principal is deposited. At time t, in years, (4/12 < t < 1) the value of the fund has increased to 62,000 and 10,000 is withdrawn. On January 1 of the next year, the investment account is worth 55,000. The approximate dollar-weighted rate of return (using the simple interest approximation) is equal to the time-weighted rate of return for the year. Calculate t.

Solution :

It is given that :

Worth of investment account on 1st Jan = 50,000

Worth of investment account on 1st Jan next year = 55,000

New principal deposited = 8000

Therefore the interest earned = 55,000 - 50,000 - 8,000 + 10,000

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Therefore,

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$t=\frac{7000-0.13667(45333.33)}{1366.7}$

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Thus, time - weighted rate of the return = 0.5885

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