Answer:
a) The probability of sampling at random a fish that is smaller in size than the value you would obtain by subtracting half the standard deviation from the average is 0.3085.
b) The probability of sampling at random a fish that is greater in size than the value you would obtain by adding half the standard deviation from the average is 0.3085.
c) The probability of sampling at random a fish that has a size between the two values is 0.383.
d) The 25th and 75 percentiles of fish size for the population using the normal distribution table is 5.69 and 5.87 respectively.
e) The probability that the average calculated will be less than the value is 0.3707.
Step-by-step explanation:
For the given data set mean 
Standard deviation 
Variance 
Here we get is
a)

b)

c)

d)
25th percentile:-
![= 25*[(n+1)/100]th term \\\\= 5.69](https://tex.z-dn.net/?f=%3D%2025%2A%5B%28n%2B1%29%2F100%5Dth%20term%20%5C%5C%5C%5C%3D%205.69)
75the percentile:-
![= 75*[(n+1)/100]th term\\\\ = 5.87](https://tex.z-dn.net/?f=%3D%2075%2A%5B%28n%2B1%29%2F100%5Dth%20term%5C%5C%5C%5C%20%3D%205.87)
e)

interesting choice of pfp
Answer:
5%
Step-by-step explanation:
(4/80)100
Set up a ratio of height over shadow length:
3.2/1.29 = X/39.25
Cross multiply:
1.29x = 3.2 * 39.25
Simplify:
1.29x = 125.6
Divide both sides by 1.29:
x = 97.364 meters
Round to the nearest meter = 97 meters
Answer:
See below
Step-by-step explanation:
For SIMPLE interest :
1210 + 1210 * .09 * 7 = <u> $ 1972.30</u>
For ANNUAL COMPOUNDING of interest
1210 ( 1 + .09)^7 = <u>$ 2211.93</u>
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I do not know which one you need....what are you studying presently?