A ball is dropped from a height of 10 feet and returns to a height that is one-half of the height from which it fell. The ball c
ontinues to bounce half the height of the previous bounce each time. How far will the ball have traveled vertically when it hits the ground for the fourth time? It might be helpful to sketch the path of the ball.
You take 143.75 and multiply by .3 to find the amount you will discount from 145.75, to get 102.025. Then multiply that by .095 to get 9.692375. Subtract that from 102.025 to get 92.33.
The answer is the vector PQ has (4-1, 8-2) as components, so it is vecPQ= (3, 6) using the definition the distance PQ= sqrt ( 3²+6²)= sqrt(9+36)=sqrt(45)
