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NNADVOKAT [17]
2 years ago
6

The diameter of the inscribed circle in a regular hexagon is 4√3 inches long. What is the perimeter of this regular hexagon?

Mathematics
1 answer:
barxatty [35]2 years ago
3 0

Answer:

12√3 inches or 20.785 inches.

Step-by-step explanation:

A regular hexagon can be defined as a polygon with 6 sides.

The formula for the perimeter of a regular hexagon =

6 × the length of the sides of the hexagon.

From the above question, we are told that there is an inscribed circle I'm the hexagon with a diameter of 4√3 inches long

Step 1

Find the radius of the circle

Radius of the circle = 4√3/2 = 2√3 inches

Step 2

The radius of the inscribed circle = Length of one of the sides of a regular hexagon.

Hence, the perimeter of the regular hexagon = 6 × 2√3

= 12√3 inches

= 20.784609691 inches.

Approximately 20.785 inches

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Read 2 more answers
Given f(x) = -x + 5, find f(-3).<br> Answer:
user100 [1]

Hey there!

<u>Find </u><u>f(</u><u>-</u><u>3</u><u>)</u><u> </u><u>:</u>

  • Answer :

f(-3) = 8 ✅

  • Explanation :

f(x) = -x + 5

<em>></em><em>></em><em> </em><em>Substitute </em><em>-</em><em>3</em><em> </em><em>for </em><em>x </em><em>in </em><em>f(</em><em>x)</em><em> </em><em>:</em><em> </em>

f(-3) = -(-3) + 5

f(-3) = 3 + 5

f(-3) = 8

Therefore, your answer is f(-3) = 8

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