Ask question

Ask question

All categories

3 years ago

8

Judy bought her tent on sale .The same price was $70 off the original price . Judy also used a coupon for an extra $15 off if Ju

dy paid $125 for the tent , what was it's original price

2 answers:

xxTIMURxx [149]3 years ago

5 0

Answer:the original price is $210

Step-by-step explanation:

Let x represent the original price of the tent. She bought it at price that is $70 off the original price. This means that $70 was taken off the original price.The amount after the discount has been removed would be

x - 70

Judy also used a coupon for an extra $15 off. This means that the amount the Judy finally paid for the tent would be

x - 70 - 15

if Judy paid $125 for the tent, it means that

x - 70 - 15 = 125

x = 125 + 70 + 15

x = $210

Lena [83]3 years ago

4 0

Answer:210

Step-by-step explanation:

175+70+15=210

You might be interested in

Did I get this right?

natima [27]

Answer: Yes, the answer is 40 quarters.

Step-by-step explanation:

1. You need to remember that 4 quarters make a dollar.

2. Keeping this on mind, you can make a Rule of three, as following: If there are 4 quarters in 1 dollar, how many quarters are in 10 dollars?

Then:

4 quarters-------1 dollar

$x$ ---10 dollars

$x=\frac{(10dollars)(4quarters)}{1dollar}\\x=40quarters$

3. Therefore, there are 40 quarters in one roll.

7 0

3 years ago

we believe that 42% of freshmen do not visit their counselors regularly. For this year, you would like to obtain a new sample to

Maksim231197 [3]

Answer:

A sample of 1077 is required.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is of:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

42% of freshmen do not visit their counselors regularly.

This means that $\pi = 0.42$

98% confidence level

So $\alpha = 0.02$ , z is the value of Z that has a pvalue of $1 - \frac{0.02}{2} = 0.99$ , so $Z = 2.327$ .

How large of a sample size is required?

A sample size of n is required, and n is found when M = 0.035. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.035 = 2.327\sqrt{\frac{0.42*0.58}{n}}$

$0.035\sqrt{n} = 2.327\sqrt{0.42*0.58}$

$\sqrt{n} = \frac{2.327\sqrt{0.42*0.58}}{0.035}$

$(\sqrt{n})^2 = (\frac{2.327\sqrt{0.42*0.58}}{0.035})^2$

$n = 1076.8$

Rounding up:

A sample of 1077 is required.

3 0

3 years ago

In 2008 the Better Business Bureau settled 75% of complaints they received (USA Today, March 2, 2009). Suppose you have been hir

Ede4ka [16]

Answer:

Explained below.

Step-by-step explanation:

According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

$\mu_{\hat p}= p$

The standard deviation of this sampling distribution of sample proportion is:

$\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}$

(a)

The sample selected is of size <em>n</em> = 450 > 30.

Then according to the central limit theorem the sampling distribution of sample proportion is normally distributed.

The mean and standard deviation are:

$\mu_{\hat p}=p=0.75\\\\\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.75(1-0.75)}{450}}=0.0204$

So, the sampling distribution of sample proportion is $\hat p\sim N(0.75,0.0204^{2})$ .

(b)

Compute the probability that the sample proportion will be within 0.04 of the population proportion as follows:

$P(p-0.04$

$=P(-1.96$

Thus, the probability that the sample proportion will be within 0.04 of the population proportion is 0.95.

(c)

The sample selected is of size <em>n</em> = 200 > 30.

Then according to the central limit theorem the sampling distribution of sample proportion is normally distributed.

The mean and standard deviation are:

$\mu_{\hat p}=p=0.75\\\\\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.75(1-0.75)}{200}}=0.0306$

So, the sampling distribution of sample proportion is $\hat p\sim N(0.75,0.0306^{2})$ .

(d)

Compute the probability that the sample proportion will be within 0.04 of the population proportion as follows:

$P(p-0.04$

$=P(-1.31$

Thus, the probability that the sample proportion will be within 0.04 of the population proportion is 0.81.

(e)

The probability that the sample proportion will be within 0.04 of the population proportion if the sample size is 450 is 0.95.

And the probability that the sample proportion will be within 0.04 of the population proportion if the sample size is 200 is 0.81.

So, there is a gain in precision on increasing the sample size.

6 0

2 years ago

C= 5/9 (F−32)

Grace [21]

Answer:

C = 5/9 (F - 32)

This is a temperature scale change comparison.

By this we understand, that ,

1°C = 5/9°F

Which is equal to, 5/9°F = 1°C

These two statements are satisfied by I. and II.

So, the correct answers are, I. and II.

If my answer helped, kindly mark me as the brainliest!

Thank You!!

5 0

3 years ago

Jaina and Tomas compare their compound interest accounts to see how much they will have in the accounts after three years. They

stellarik [79]

Formula for compound interest is

Interest = Amount - Principal

Interest = $P(1+r)^{t}$ - P

Where r = rate in percent

t = time in years

For Jaina,

P = $300

r= 7%

t = 3 yrs

So, Interest = $300(1+0.07)^{3}$ - 300

For Tomas

P = $400

r= 4%

t = 3 yrs

So, Interest = $400(1+0.04)^{3}$ - 400

So pair of equations for Jaina and Tomas are

Interest = $300(1+0.07)^{3}$ - 300

Interest = $400(1+0.04)^{3}$ - 400

5 0

3 years ago

Read 2 more answers