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hoa [83]
3 years ago
5

A wall clock loses 3 minutes each day. The clock showed the correct time on Monday at 11:00 am. What time will the clock show at

11:00 on the next Friday?​
Mathematics
1 answer:
Step2247 [10]3 years ago
8 0

Answer:

10:48am

Step-by-step explanation:

Since the clock loses 3 minutes each day and from monday 11:00am to friday 11:00 am there are 4 days, the amount of minutes the clock will lose is:

4 * 3 = 12 minutes

So the time in the clock at 11:00 am on friday will be 10:48am.

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What would the bottles purchased be and what would the bottles recycled be?
N76 [4]

Part A

Your problem statement already shows you the conversion.

Bottles purchased: 5×10¹⁰

Bottles recycled: 8.3×10⁹

Part B

The ratio of bottles purchased to bottles recycled is

... (5×10¹⁰)/(8.3×10⁹) = 0.6×10¹ = 6.0

The number of bottles purchased is 6 times the number of bottles recycle.

5 0
3 years ago
Can I get some help please
Mamont248 [21]
-2(-2)+3=7
-2(0)+3=3
-2(4)+3=-5
3 0
3 years ago
Does anyone know how to solve this? It’s really starting to stress me out.
bekas [8.4K]

Answer:

π − 12

Step-by-step explanation:

lim(x→2) (sin(πx) + 8 − x³) / (x − 2)

If we substitute x = u + 2:

lim(u→0) (sin(π(u + 2)) + 8 − (u + 2)³) / ((u + 2) − 2)

lim(u→0) (sin(πu + 2π) + 8 − (u + 2)³) / u

Distribute the cube:

lim(u→0) (sin(πu + 2π) + 8 − (u³ + 6u² + 12u + 8)) / u

lim(u→0) (sin(πu + 2π) + 8 − u³ − 6u² − 12u − 8) / u

lim(u→0) (sin(πu + 2π) − u³ − 6u² − 12u) / u

Using angle sum formula:

lim(u→0) (sin(πu) cos(2π) + sin(2π) cos(πu) − u³ − 6u² − 12u) / u

lim(u→0) (sin(πu) − u³ − 6u² − 12u) / u

Divide:

lim(u→0) [ (sin(πu) / u) − u² − 6u − 12 ]

lim(u→0) (sin(πu) / u) + lim(u→0) (-u² − 6u − 12)

lim(u→0) (sin(πu) / u) − 12

Multiply and divide by π.

lim(u→0) (π sin(πu) / (πu)) − 12

π lim(u→0) (sin(πu) / (πu)) − 12

Use special identity, lim(x→0) ((sin x) / x ) = 1.

π (1) − 12

π − 12

3 0
3 years ago
The following numerically ordered sequence of numbers has a mean of 17 and a median of 18.
Arisa [49]

a= 9

b= 19

hope this helps

8 0
3 years ago
Three siblings collect rare coins. Howany rare coins does each sibling have if theyhave a total of 49 rare coins?
Dafna1 [17]
49 divided by 3 = 16.33  
Each sibling has about 16 rare coins.
7 0
3 years ago
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