Hi there!
a.
We know that:
Begin by determining the forces in the vertical direction:
W = weight of traffic light
T₁sinθ = vertical component of T₁
T₂sinθ = vertical component of T₂
b.
The ropes provide a horizontal force:
T₁cosθ = Horizontal component of T1
T₂cosθ = Horizontal component of T2
Thus:
0 = T₁cosθ - T₂cosθ
T₁cosθ = T₂cosθ
T₁ = T₂
c.
Since the angles for both ropes are the same, we can say that:
T₁ = T₂
Sum the forces:
ΣFy = T₁sinθ + T₁sinθ - W = 0
2T₁sinθ = W
d.
Now, we can begin by solving for the tensions:
2T₁sinθ = W
Answer:
Explanation:
a) Force of friction = μ R where μ is coefficient of kinetic friction and R is reaction force
R = mg where m is mass of the block
Force of friction F = μ x mg
= .173 x 12.2 x 9.8
= 20.68 N
b ) Only force of friction is acting on the body so
deceleration = force / mass = 20.68 / 12.2 = 1.7 m /s²
acceleration = - 1.7 m /s²
c )
v² = u² - 2 a s
v = 0 , u = 3.9 m /s
a = 1.7 m /s
0 = 3.9² - 2 x 1.7 x s
s = 4.47 m
Answer:
is the density of the oil
Explanation:
Given:
- height of oil column,
- oil column height that is more than the water column height in the other arm,
<u>Now from the given it is clear that the height of water column is:</u>
Now according to the pressure balance condition of fluid columns:
Pressure due to water column = Pressure due to oil column
is the density of the oil
Do you mean period of time, period as in English spelling, or a period that concerns the medical field?
The dimension of soccer field in ft is 377.315 ft long and 277.885 ft in width.
The dimension of soccer field in ft is 4527.78 in long and 3334.62 in in width.
As it is given that 1 m =3.281 ft
Therefore the length of the soccer field in ft is
115*3.281=377.315 ft
And width of the field is 85*3.281=277.885 ft
We know that 1 ft =12 in
Therefore the length of the soccer field in in is
377.315*12=4527.78 in
And width of the field is 277.885 *12=3334.62 in
