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2 years ago

8

A soccer ball is released from rest at the top of a grassy incline. After 8.6 seconds, the ball travels 87 meters and 1.0 s afte

r this, the ball reaches the bottom of the incline. What was the magnitude of the ball's acceleration, assume it to be constant

2 answers:

lana66690 [7]2 years ago

6 0

Answer: The ball's acceleration is 2.35 m/s2

Explanation: Please see the attachment below

Luden [163]2 years ago

6 0

Answer:

The acceleration is $a= 2.4 \ m/s^2$

Explanation:

From the question we are told that

The distance covered is $d = 87 \ m$

The time taken is $t = 8.6 \ s$

Time taken reach the bottom is $t_b = 1 \ s$

According to the equation of motion

$S = ut + \frac{1}{2} at^2$

since the ball started at rest u = 0 m/s

substituting values

$87 = 0 + \frac{1}{2} * a * (8.6)^2$

=> $a = \frac{2 * 87}{8.6^2}$

=> $a= 2.4 \ m/s^2$

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