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3 years ago

8

A soccer ball is released from rest at the top of a grassy incline. After 8.6 seconds, the ball travels 87 meters and 1.0 s afte

r this, the ball reaches the bottom of the incline. What was the magnitude of the ball's acceleration, assume it to be constant

2 answers:

lana66690 [7]3 years ago

6 0

Answer: The ball's acceleration is 2.35 m/s2

Explanation: Please see the attachment below

Luden [163]3 years ago

6 0

Answer:

The acceleration is $a= 2.4 \ m/s^2$

Explanation:

From the question we are told that

The distance covered is $d = 87 \ m$

The time taken is $t = 8.6 \ s$

Time taken reach the bottom is $t_b = 1 \ s$

According to the equation of motion

$S = ut + \frac{1}{2} at^2$

since the ball started at rest u = 0 m/s

substituting values

$87 = 0 + \frac{1}{2} * a * (8.6)^2$

=> $a = \frac{2 * 87}{8.6^2}$

=> $a= 2.4 \ m/s^2$

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Answer:

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Explanation:

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3 years ago

If a soap bubble is 115 nm thick, what wavelength is most strongly reflected at the center of the outer surface when illuminated

sp2606 [1]

Answer:

$611.8$ nm

Explanation:

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3 years ago

(a) Triply charged uranium-235 and uranium-238 ions are being separated in a mass spectrometer. (The much rarer uranium-235 is u

stiv31 [10]

Answer:

(a) 2.5 cm

(b) Yes

Solution:

As per the question:

Mass of Uranium-235 ion, m = $3.95\times 10^{- 25}\ kg$

Mass of Uranium- 238, m' = $3.90\times 10^{- 25}\ kg$

Velocity, v = $3.00\times 10^{5}\ m/s$

Magnetic field, B = 0.250 T

q = 3e

Now,

To calculate the path separation while traversing a semi-circle:

$\Delta x = 2(R_{U_{35}} - 2R_{U_{38}})$

The radius of the ion in a magnetic field is given by:

R = $\frac{mv}{qB}$

$\Delta x = 2(R_{U_{35}} - 2R_{U_{38}})$

$\Delta x = 2(\frac{mv}{qB} - \frac{m'v}{qB})$

$\Delta x = 2(\frac{m - m'}{qB}v)$

Now,

By putting suitable values in the above eqn:

$\Delta x = 2(\frac{3.95\times 10^{- 25} - 3.90\times 10^{- 25}}{3\times 1.6\times 10^{- 19}\times 0.250}\times 3.00\times 10^{5}) = 2.5\ cm$

$\Delta x = 1.25\ cm$

(b) Since the order of the distance is in cm, thus clearly this distance is sufficiently large enough in practical for the separation of the two uranium isotopes.

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3 years ago