Question

A soccer ball is released from rest at the top of a grassy incline. After 8.6 seconds, the ball travels 87 meters and 1.0 s after this, the ball reaches the bottom of the incline. What was the magnitude of the ball's acceleration, assume it to be constant

Answer 1

Answer: The ball's acceleration is 2.35 m/s2

Explanation: Please see the attachment below

Answer 2

Answer:

The acceleration is  $a= 2.4 \ m/s^2$

Explanation:

From the question we are told that

   The distance covered is  $d = 87 \ m$

    The time taken is  $t = 8.6 \ s$

    Time taken reach the bottom is  $t_b = 1 \ s$

 According to the equation of motion

           $S = ut + \frac{1}{2} at^2$

since the ball started at rest u =  0 m/s  

     substituting values

    $87 = 0 + \frac{1}{2} * a * (8.6)^2$

=>     $a = \frac{2 * 87}{8.6^2}$

=>      $a= 2.4 \ m/s^2$