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Lyrx [107]
4 years ago
5

Do animals fart and do all animals blink and do animals have the same trait of humans

Physics
2 answers:
pantera1 [17]4 years ago
8 0
Uh yes they do fart and blink. Like very living person, and animal. They do have the same traits, as that to humans, but their biology is set up differently. They are stronger and quicker.
I'm not going to state that humans are animals, because I don't agree. Humans are NOT animals!!! But that's my belief, oppose as you like.
I think the best way to answer this question, is to imagine being an animal. Possibly a wild animal. What do you do? How do you find food? Where do you sleep? See, usually humans know how to be disgusted about living in unsanitary and unsafe environments. I mean looking at the traits, they're biology is just set up differently from humans.

I hope this helps.<span />
muminat4 years ago
4 0

Answer:

This is quite a controversial question to ask.

Explanation:

in short words, <em>yes, </em>animals can normally fart like humans can. it is not because they share traits like us, their body is usually built the same, it is simply just a way to get rid of unecessary gasses in the lower build area. Usually, most animals do blink aswell. of course, there are always going to be <u><em>exceptions. </em></u>

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A tank having a volume of 0.85 m 3 initially contains water as a two-phase liquid-vapor mixture at 260 o C and a quality of 0.7.
Keith_Richards [23]

Answer:=14,160 kJ

Explanation: Let m1 and m2 be the initial and final amounts of mass within the tank, respectively. The steam properties are listed in the table below

Specific Internal SpecificTemp Pressure Volume Energy Enthalpy Quality Phase

C MPa m^3/kg kJ/kg kJ/kg

1 260 4.689 0.02993 2158 2298 0.7 Liquid Vapor Mixture

2 260 4.689 0.0422 2599 2797 1 Saturated Vapor

The mass initially contained in the tank is m1 = V/v1

m1 =0.85 m^3 /0.02993 m^3 /kg

= 28.4 kg

The mass finally contained in the tank is

m2 =V2/v

= 0.85 m^3 /0.0422 m^3 /kg

= 20.14 kg

The heat transfer is then

Qcv = m2u2 − m1u1 − he(m2 − m1)

Qcv = (20.14)(2599) − (28.4)(2158) − (2797)(20.14 − 28.4) = 14,160 kJ

4 0
4 years ago
An auto race takes place on a circular track. A car completes one lap in a time of 18.0 s, with an average tangential speed of 4
eduard

Answer:

(A) 0.3488 rad/sec

(B) 124.246 m                

Explanation:

We have given car completes one revolution in 18 sec'

So time period T= 18 sec

Tangential speed v = 43.4 m/sec

(A) Angular velocity is given by \omega =\frac{2\pi }{T}=\frac{2\times 3.14}{18}=0.3488rad/sec

(B) Tangential velocity is given v = 43.4 m /sec

We know that v=\omega r

r=\frac{v}{\omega }=\frac{43.4}{0.3488}=124.426m

4 0
3 years ago
Suppose that the collector is held at a small negative voltage with respect to the grid. Will the accelerated electrons reach th
Leona [35]

Answer:

B) Yes, but only those electrons with energy greater than the potential difference established between the grid and the collector will reach the collector.

Explanation:

In the case when the collector would held at a negative voltage i.e. small with regard to grid So yes the accelerated electrons would be reach to the collecting plate as the kinetic energy would be more than the potential energy that because of negative potential

so according to the given situation, the option b is correct

And, the rest of the options are wrong

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Blababa [14]

Answer:

d

Explanation:

4 0
3 years ago
Which of the following statements is correct.
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The answer is C, as the frequency gets higher the wavelength gets shorter
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