The magnitude of the electric field due to the particle at the given distance is 
.
<h3>Electric field strength</h3>
The electric field strength of a charged particle is the force per unit charge in the given field.
The electric field strength of a charge is given as;
where;
- k is Coulomb's constant
- q is the charge
- r is the distance
Thus, the magnitude of the electric field due to the particle at the given distance is .
Learn more about electric field here: brainly.com/question/14372859
Answer: To isolate the unknown substances, of which only tiny amounts were present, the Curies were the first to use a new method of chemical analysis. They employed various standard (but sometimes demanding) chemical procedures to separate the different substances in pitchblende.
Explanation:
Fc=mv2/r formula of centripetal force will be applied here with radius mass and velocity described in the above question
Answer:
B. 2nmv
Explanation:
Pressure is force over area.
P = F / A
Force is mass times acceleration.
F = ma
Acceleration is change in velocity over change in time.
a = Δv / Δt
Therefore:
F = m Δv / Δt
P = m Δv / (A Δt)
The total mass is nm.
The change in velocity is Δv = v − (-v) = 2v.
A = 1 and Δt = 1.
Plugging in:
P = (nm) (2v) / (1 × 1)
P = 2nmv
