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3 years ago

Circle the expressions that represent 10% of the original cost

Mathematics

1 answer:

Anni [7]3 years ago

5 0

Answer:

What are the choices?

Step-by-step explanation:

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Which statement is true about figures ABCD and A′B′C′D′? (1 point)

sladkih [1.3K]

Answer:

Step-by-step explanation:

A'B'C'D' is obtained by rotating ABCD 180° counterclockwise about the origin and then reflecting it across the x-axis.

A(2, -2) is mapped to A'(-2, -2)

B(1, -4) is mapped to B'(-1, -4)

C(0, -2) is mapped to C'(0, -2)

D(1, -1) is mapped to D'(-1, -1)

If we rotate counterclockwise 180°, every point (x, y) is mapped to (-x, -y):

A(2, -2) gets mapped to (-2, 2)

B(1, -4) gets mapped to (-1, 4)

C(0, -2) gets mapped to (0, 2)

D(1, -1) gets mapped to (-1, 1)

Reflecting these images across the x-axis will then map (x, y) to (x, -y):

(-2, 2) gets mapped to (-2, -2)

(-1, 4) gets mapped to (-1, -4)

(0, 2) gets mapped to (0, -2)

(-1, 1) gets mapped to (-1, -1)

These new coordinates are the same as A'B'C'D'.

3 0

2 years ago

If one pound = rupees 135 and dollar =105 rupees then convert the pound 63 into Dollar

enot [183]

Answer:

Step-by-step explanation:

£63 = 135 × 63

= Rs . 8505

Rs . 8505 = 8505 / 105

= $81

6 0

2 years ago

PLEASE HELP ASAP!! means a lot!!

egoroff_w [7]

The correct answer is:
$B) \: y + 1 = \frac{4}{3} (x - 9)$

6 0

3 years ago

Three security cameras were mounted at the corners of a triangles parking lot. Camera 1 was 110 ft from camera 2, which was 137

Nata [24]

Answer:

Camera 2nd has to cover the maximum angle, i.e. $78.70^\circ$ .

Step-by-step explanation:

Please have a look at the triangular park represented as a triangle $\triangle ABC$ with sides

a = 110 ft

b = 158 ft

c = 137 ft

1st camera is located at point C, 2nd camera at point B and 3rd camera at point A respectively.

We can use law of cosines here, to find out the angles $\angle A, \angle B, \angle C$

As per Law of cosine:

$cos C = \dfrac{a^{2}+b^2-c^2 }{2ab}\\cos B = \dfrac{a^{2}+c^2-b^2 }{2ac}\\cos A = \dfrac{b^{2}+c^2-a^2 }{2bc}$

Putting the values of a,b and c to find out angles $\angle A, \angle B, \angle C$ .

$cos C = \dfrac{110^{2}+158^2-137^2 }{2\times 110 \times 158}\\\Rightarrow cos C = \dfrac{12100+24964-18769 }{24760}\\\Rightarrow cos C =0.526\\\Rightarrow C = 58.24^\circ$

$cos B = \dfrac{110^{2}+137^2-158^2 }{2\times 110 \times 137}\\\Rightarrow cos B = \dfrac{12100+18769 -24964}{30140}\\\Rightarrow cos B = \dfrac{5905}{30140}\\\Rightarrow cos B =0.196\\\Rightarrow B = 78.70^\circ$

$cos A = \dfrac{158^{2}+137^2-110^2 }{2\times 158 \times 137}\\\Rightarrow cos A = \dfrac{24964+18769-12100}{43292}\\\Rightarrow cos A = \dfrac{31633}{43292}\\\Rightarrow cos A = 0.731\\\Rightarrow A = 43.05^\circ$

Camera 2nd has to cover the maximum angle, i.e. $78.70^\circ$ .

6 0

3 years ago

Which decimals as the same value as 2 divided by 5

LenKa [72]

Answer:

anything that ends in 0 like .10

5 0

2 years ago

Read 2 more answers