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2 years ago

Divide. −425÷(−5) −2225 −825 825 2225

Mathematics

1 answer:

Alex17521 [72]2 years ago

6 0

Answer: The correct answer would be -85.

Step-by-step explanation: This is because the -5 becomes positive because it is inside parentheses.

This would make the expression: -425 ÷ 5.

-425 ÷ 5 is equal to -85.

Hope this helps and have a nice day! :)

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Solving Equations by Adding or Subtracting Fractions<br> Show all working<br> n + 23 = 19

dlinn [17]

N+23=19
-23 -23 Takeaway 23 from both sides
Answer is N= - 4

7 0

2 years ago

It appears that people who are mildly obese are less active than leaner people. One study looked at the average number of minute

Molodets [167]

Answer:

10.38% probability that the mean number of minutes of daily activity of the 6 mildly obese people exceeds 410 minutes.

99.55% probability that the mean number of minutes of daily activity of the 6 lean people exceeds 410 minutes

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$ .

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Mildly obese

Normally distributed with mean 375 minutes and standard deviation 68 minutes. So $\mu = 375, \sigma = 68$

What is the probability (±0.0001) that the mean number of minutes of daily activity of the 6 mildly obese people exceeds 410 minutes?

So $n = 6, s = \frac{68}{\sqrt{6}} = 27.76$

This probability is 1 subtracted by the pvalue of Z when X = 410.

$Z = \frac{X - \mu}{s}$

$Z = \frac{410 - 375}{27.76}$

$Z = 1.26$

$Z = 1.26$ has a pvalue of 0.8962.

So there is a 1-0.8962 = 0.1038 = 10.38% probability that the mean number of minutes of daily activity of the 6 mildly obese people exceeds 410 minutes.

Lean

Normally distributed with mean 522 minutes and standard deviation 106 minutes. So $\mu = 522, \sigma = 106$

What is the probability (±0.0001) that the mean number of minutes of daily activity of the 6 lean people exceeds 410 minutes?

So $n = 6, s = \frac{106}{\sqrt{6}} = 43.27$

This probability is 1 subtracted by the pvalue of Z when X = 410.

$Z = \frac{X - \mu}{s}$

$Z = \frac{410 - 523}{43.27}$

$Z = -2.61$

$Z = -2.61$ has a pvalue of 0.0045.

So there is a 1-0.0045 = 0.9955 = 99.55% probability that the mean number of minutes of daily activity of the 6 lean people exceeds 410 minutes

6 0

3 years ago

Evaluate f(−1)=−3x^3 + 2x^2

Sholpan [36]

Answer:

Step-by-step explanation:

f(-1)= -3(-1)³+2(-1)²

= -3(-1)+2(1)

= 3+2

5 0

2 years ago

Create a function that has a derivative of f(x) = 2x + 1 at a given input value of your choice.

Taya2010 [7]

The opposite operation to taking a derivative is an integral. Integrate to find original function.

f(x) = x^2 + x + C

C is constant because we didn't have bounds on the integral. it lets you choose the input value let's say is just (1,0)

0 = 1 + 1 + C
- 2 = C

function at input value (1,0)
f(x) = x^2 + x - 2

now if you check by taking derivative is :
f' = 2x + 1

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2 years ago

Of th 30 girls who tried out for the lacrosse team team at Euclid middle school , 12 were selected. Of the 40 boys show tried ou

Harman [31]

12/30 is simplified to 2/5 and<span>number of students trying out the same for both boys and girls</span> 16/40 is also simplified to 2/5 so YES the number of students trying out is the same for both boys and girls. I hope this helps :)

3 0

3 years ago