We have that
<span>p(t)=-3t^2+18t-4
using a graphing tool, we can see the maximum of the graph
(see the attached figure)
A) </span><span>In what year of operation does Mr. Cash’s business show maximum profit?
</span>
Mr. Cash’s business show maximum profit at year 3 (maximum in the parabole)
<span>B) What is the maximum profit?
23 (hundred of thousand of dollars) = 2.300.000 dollars
</span>c) What time will it be two late?
(This is the time when the graph crosses zero and the profits turn into losses )
5.77 years, or an estimate of about 69 months.
Answer:
9x^4+21x+6=0
Step-by-step explanation:
( 3x^2)^2+7(3x +2) -8=0
((3^2)*(x^2)^2)+(7*3x)+(7*2)-8=0
9(x^4)+21x+14-8=0
9x^4+21x+6=0
Step one: divide both sides by -2.3 to get X by itself: X=-.2. :)
Answer:
Answer is D
Step-by-step explanation:
just took the test and got it right
Please mark brainlest
Answer:
The probability is 0.003
Step-by-step explanation:
We know that the average
is:

The standard deviation
is:

The Z-score is:

We seek to find

For P(x>800) The Z-score is:



The score of Z = 3 means that 800 is 3 standard deviations from the mean. Then by the rule of the 8 parts of the normal curve, the area that satisfies the conficion of 3 deviations from the mean has percentage of 0.15%
So

For P(x<200) The Z-score is:



The score of Z = -3 means that 200 is 3 standard deviations from the mean. Then by the rule of the 8 parts of the normal curve, the area that satisfies the conficion of 3 deviations from the mean has percentage of 0.15%
So

Therefore


