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RSB [31]
3 years ago
6

Keeping in mind the rules for significant figures, determine how many milliliters there are in 0.073 gallons. 1 gallon = 4 quart

s, 1 liter = 1.057 quarts
Mathematics
1 answer:
andreev551 [17]3 years ago
3 0

we are given

there are in 0.073 gallons

we can see that there are two non-zero places after decimals

so, there are two siginificant figures

step-1: Change gallons to quarts

we know that

1 gallon = 4 quarts

so, we can write as

0.073gallons=0.073*1gallon

0.073gallons=0.073*4quarts

0.073gallons=0.292quarts

step-2: Change into liter

0.073gallons=0.292quarts

we know that

1 liter = 1.057 quarts

or

1 quart=\frac{1}{1.057} litre

0.073gallons=0.292*1quarts

0.073gallons=0.292*\frac{1}{1.057} litre

0.073gallons=0.27625 litre

step-3: Change into millilitre

we know that

1L=1000mL

0.073gallons=0.27625*1 litre

0.073gallons=0.27625*1000 mL

Since, it is asking for only two significant figures

so, we can also write as

0.073gallons=0.28*1000 mL

0.073gallons=280 mL...................Answer


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if in the study of the lifetime of 60-watt light bulbs it was desired to have a margin of error no larger than 6 hours with 99%
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The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

The lifetime (in hours) of a 60-watt light bulb is a random variable that has a Normal distribution with σ = 30 hours. A random sample of 25 bulbs put on test produced a sample mean lifetime of = 1038 hours.

If in the study of the lifetime of 60-watt light bulbs it was desired to have a margin of error no larger than 6 hours with 99% confidence, how many randomly selected 60-watt light bulbs should be tested to achieve this result?

Given Information:

standard deviation = σ = 30 hours

confidence level = 99%

Margin of error = 6 hours

Required Information:

sample size = n = ?

Answer:

sample size = n ≈ 165

Step-by-step explanation:

We know that margin of error is given by

Margin of error = z*(σ/√n)

Where z is the corresponding confidence level score, σ is the standard deviation and n is the sample size

√n = z*σ/Margin of error

squaring both sides

n = (z*σ/Margin of error)²

For 99% confidence level the z-score is 2.576

n = (2.576*30/6)²

n = 164.73

since number of bulbs cannot be in fraction so rounding off yields

n ≈ 165

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