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lbvjy [14]
3 years ago
15

Rewrite each fraction with a denominator of 10 7/2 3/5

Mathematics
1 answer:
Vaselesa [24]3 years ago
8 0

Answer:

  • \frac{7}{2}=\frac{35}{10}
  • \frac{3}{5}=\frac{6}{10}

Step-by-step explanation:

Given the fraction

\frac{7}{2}

Multiplying numerator and denominator by 5

\frac{7}{2}\times \frac{5}{5}

=\frac{35}{10}

Therefore,

  • \frac{7}{2}=\frac{35}{10}

Similarly,

Given the fraction

\frac{3}{5}

Multiplying numerator and denominator by 2

\:\frac{3}{5}\times \:\frac{2}{2}

\frac{3}{5}\times \:\frac{2}{2}=\frac{6}{10}

Therefore,

  • \frac{3}{5}=\frac{6}{10}
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A jar contains 8 red marbles numbered 1 to 8 and 7 blue marbles numbered 1 to 7. A marble is drawn at random from the jar. Find
Shkiper50 [21]

Answer:

Therefore the probability that the marble is blue or even numbered is \frac{11}{15}

Step-by-step explanation:

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It is denoted by P.

Probability= \frac{\textrm{favorable outcomes}}{\textrm{Total outcomes}}

Given that a jar contains 8 red marbles and 7 blue marbles.

Total number of marbles = (8+7) = 15

Let A = Event of getting a blue marble

B= Event of getting of even marble.

Even number blue marbles are 2, 4,6

Even number red marbles are 2, 4,6,8

The number of even marbles are =(3+4)=7

The probability of getting a blue marble is P(A)

=\frac{\textrm{Total number of blue marbles}}{\textrm{Total number of blue marbles}}

=\frac{7}{15}

The probability of getting a even marble  is P(B)

=\frac{\textrm{The number of even number marbles}}{\textrm{Total number of marbles}}

=\frac{7}{15}

The probability of getting a even numbered blue marble P(A∩B)

=\frac{3}{16}

P(blue marble or even- numbered)

=P(A∪B)

=P(A)+P(B)-P(A∩B)

=\frac{7}{15} +\frac{7}{15}-\frac{3}{15}

=\frac{11}{15}

Therefore the probability that the marble is blue or even numbered is \frac{11}{15}

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3 years ago
Rewrite each statement using brackets to make a true statement 6.7 decided by 0.3+5.2x3.9=4.75.
mezya [45]

(0.35+5.2)(3.9)=4.75

5 0
3 years ago
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