Answer:
The reaction can produce 287 grams of iron(II) carbonate
Explanation:
To solve this question we must find the moles of iron(II) chloride that react. Using the chemical equation we can find the moles of iron(II) carbonate and its mass -Molar mass FeCO3: 115.854g/mol-
<em>Moles FeCl2:</em>
1.24L * (2.00mol / L) = 2.48 moles FeCl2
As 1 mol FeCl2 produce 1 mol FeCO3, the moles of FeCO3 = 2.48 moles
<em>Mass FeCO3:</em>
2.48mol * (115.854g / mol) =
<h3>The reaction can produce 287 grams of iron(II) carbonate</h3>
Answer:
The cell potential is 0.0296V
Explanation:
Please see the attachment below
Answer:
506.912 L
Explanation:
From the question given above, the following data were obtained:
Number of mole of O₂ = 22.63 moles
Volume of O₂ =?
Recall:
1 mole of a gas occupy 22.4 L at STP.
With the above information, we obtained the volume occupied by 22.63 moles of O₂ as follow:
1 mole of O₂ occupied 22.4 L at STP.
Therefore, 22.63 moles of O₂ will occupy = 22.63 × 22.4 = 506.912 L at STP.
Thus, 22.63 moles of O₂ is equivalent to 506.912 L.
Answer:
<h2>225 g</h2>
Explanation:
The mass of a substance when given the density and volume can be found by using the formula
mass = Density × volume
From the question we have
mass = 0.9 × 250
We have the final answer as
<h3>225 g</h3>
Hope this helps you
Molecular mass of C₂H₄ is,
M = 2×12 + 4×1 g/mol
M = 28 g/mol
Moles of C₂H₄ in 5.6 g of C₂H₄ :
n = 5.6/28 mol
n = 0.2 mol
Now, 1 mol of C₂H₄ contains 2 moles of carbon.
So, number of moles of carbon are :
n = 0.4 mol
We know, 1 mol of any atom contains 6.022 × 10²³ atoms.
So, number of carbon atoms are :
Hence, this is the required solution.
