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labwork [276]
2 years ago
15

What is the symbol for temperature? m q T J

Chemistry
1 answer:
Tcecarenko [31]2 years ago
6 0

Answer:

T

Explanation:

m is mass

q is heat

J is energy

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What are the number of protons, electrons, and neutrons in Potassium
gayaneshka [121]
<span><span>Number of Protons-19 </span><span>Number of Neutrons-20 </span><span>Number of Electrons-<span>19</span></span></span>
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4 years ago
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What is an isotope? Explain why isotopes having different number of neutrons are still considered to be the same element on the
Mazyrski [523]

Isotopes of any given factor all incorporate the equal variety of protons, so they have the identical atomic wide variety (for example, the atomic wide variety of helium is usually 2). Isotopes of a given factor include exceptional numbers of neutrons, therefore, special isotopes have special mass numbers.

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What is the equation for "acid dissociation constant" of "carbonic acid"
Margaret [11]

Answer:

H2CO3 = 2H+ + CO3-

Explanation:

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6 0
3 years ago
A solution is prepared by dissolving 215 grams of methanol, ch3oh, in 1000. grams of water. what is the freezing point of this s
Leya [2.2K]

Answer : The freezing point of the solution is, 260.503 K

Solution : Given,

Mass of methanol (solute) = 215 g

Mass of water (solvent) = 1000 g = 1 kg       (1 kg = 1000 g)

Freezing depression constant = 1.86^oC/m=1.86Kkg/mole

Formula used :

\Delta T_f=K_f\times m\\T^o_f-T_f=K_f\times \frac{w_{solute}}{M_{solute}\times w_{solvent}}

where,

T^o_f = freezing point of water = 100^oC=273K

T_f = freezing point of solution

K_f = freezing point constant

w_{solute} = mass of solute

w_{solvent} = mass of solvent

M_{solute} = molar mass of solute

Now put all the given values in the above formula, we get

273K-T_f=(1.86Kkg/mole)\times \frac{215g}{(32g/mole)\times (1kg)}

By rearranging the terms, we get the freezing point of solution.

T_f=260.503K

Therefore, the freezing point of the solution is, 260.503 K

6 0
3 years ago
What is the molarity of a solution containing 17.0 g of KCl in 213 mL of KCl solution?
Anarel [89]

Answer:

1.070MKCl

Explanation:

So we know that the original formula is M= n/L (n being moles of solute, L being liters of solvent)

Since we do not have liters in this problem, we would need to convert  milliliters to liters

<u>213 mL= 0.213 L</u>

We then see that we do not have moles, but we do have a mass, being <u>17.0 g.</u> we would need to convert these grams to moles, giving us <u>0.228 mol.</u>

Then, you would plug in <u>0.228 for your n</u>, and now you are ready to solve your original formula, plugging everything in.

M=n/L

M=0.228 mol/0.213L

M= 1.070MKCl

I know this was long, but I hope this helps (:

5 0
3 years ago
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