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Igoryamba
3 years ago
5

It is given that A is directly proportional to r2 and r> 0. When r=5, A=75.

Mathematics
1 answer:
torisob [31]3 years ago
3 0

Answer:

see explanation

Step-by-step explanation:

Given A is directly proportional to r² then the equation relating them is

A = kr² ← k is the constant of proportion

To find k use the condition when r = 5, A = 75 , then

75 = k × 5² = 25k ( divide both sides by 25 )

3 = k

A = 3r² ← equation of proportion

(a)

when r = 4, then

A = 3 × 4² = 3 × 16 = 48

(b)

when A = 147 , then

147 = 3r² ( divide both sides by 3 )

49 = r² ( take the square root of both sides )

r = \sqrt{49} = 7

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2 years ago
For what value(s) of k will the relation not be a function?<br> A = {(3k−4, 16), (4k, 32)}
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We won't have a function if for same value of x in (x,y) we get different values y.

So first step: figure out k so that the first coordinate (x) is the same:

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k = -4

no check the values y for the elements of the relation

x = 3k-4 = -12-4=-16

so at -16 we get (-16,16) and (-16, 32), which mean for k=-4 the relation is not a function.

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3 years ago
What is the equation of the circle whose center and radius are given.
muminat
Hello!

The equation for a circle is

(x - h)^{2}  + ( y - k)^{2} =  r^{2}

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(x - 7)^{2} + ( y + 3)^{2} = 7^{2}

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The equation is (x - 7)^{2} + ( y + 3)^{2} = 49

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