Let the numbers be n, n+2, n+4
Sum equals too= 13+2(n+4), which is 2n+21
a) Equation--> n+n+2+n+4= 2n+21
b) Solution--> 3n+6= 2n+21
=> n= 15
c) Second number--> 17 (15+2)
Third number--> 19 (15+4)
d) 15+15+2+15+4=30+21
=> 51= 51
So, the equation is true.
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Answer:
39
Step-by-step explanation:
Let the three consecutive odd numbers be:
x+2, x+4, x+6.
The sum of the consecutive numbers is 123 i.e
x+2 + (x+4) + (x+6) = 123
x + 2 + x + 4 + x + 6 = 123
3x + 12 = 123
Collect like terms
3x = 123 — 12
3x = 111
Divide both side by the coefficient of x i.e 3
x = 111/3
x = 37
Now let us find the value of the three odd numbers. This is illustrated:
1st : x + 2 = 37 + 2 = 39
2nd : x + 4 = 37 + 4 = 41
3rd : x + 6 = 37 + 6 = 43
The smallest of the three consecutive odd numbers is 39
By using the remainder theorem we found that ( x - 5 ) is the factor of function f(x) = x³ – 5x² + 7x – 35.
<h3>What is factorization?</h3>
Factorization is defined as splitting the polynomial into its most simplified form. This factor satisfies the polynomials from which it is extracted.
The factorization by using the Remainder theorem.
x - 5 ) x³ – 5x² + 7x – 35.( x ² + 7
x³ - 5x²
______________
00 7x - 35
7x - 35
-------------------------
00
Here the function is completely divided by the factor x - 5 therefore
by using the remainder theorem we found that ( x - 5 ) is the factor of function f(x) = x³ – 5x² + 7x – 35.
To know more about factorization follow
brainly.com/question/25829061
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Answer:
1.66666667 <-- repeatedly is your answer
Step-by-step explanation:
1.636x10^5 after adding or 163600 depending on the form wanted
