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3 years ago

What is the measure of ZABC?

Mathematics

1 answer:

Finger [1]3 years ago

3 0

Answer:

A. 85°

Step-by-step explanation:

By intersecting chords theorem:

$m\angle ABC= \frac{1}{2} (130 \degree + 40 \degree)$

$m\angle ABC= \frac{1}{2}\times 170 \degree$

$m\angle ABC= 85 \degree$

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Suppose the solutions of a homogeneous system of four linear equations in five unknowns are all multiples of one nonzero solutio

Akimi4 [234]

Consider a homogeneous machine of four linear equations in five unknowns are all multiples of 1 non-0 solution. Objective is to give an explanation for the gadget have an answer for each viable preference of constants on the proper facets of the equations.

Yes, it's miles true.

Consider the machine as Ax = 0. in which A is 4x5 matrix.

From given dim Nul A=1. Since, the rank theorem states that

The dimensions of the column space and the row space of a mxn matrix A are equal. This not unusual size, the rank of matrix A, additionally equals the number of pivot positions in A and satisfies the equation

rank A+ dim NulA = n

dim NulA =n- rank A

Rank A = 5 - dim Nul A

Rank A = 4

Thus, the measurement of dim Col A = rank A = five

And since Col A is a subspace of R^4, Col A = R^4.

So, every vector b in R^4 also in Col A, and Ax = b, has an answer for all b. Hence, the structures have an answer for every viable preference of constants on the right aspects of the equations.

8 0

3 years ago

The top and bottom margins of a poster 66 cm each, and the side margins are 44 cm each. If the area of the printed material on t

jasenka [17]

Answer:

width: 24 cm
height: 36 cm

Step-by-step explanation:

When margins are involved, the smallest area will be the one that has its dimensions in the same proportion as the margins. If x is the "multiplier", the dimensions of the printed area are ...

(4x)(6x) = 384 cm^2

x^2 = 16 cm^2 . . . . . divide by 24

x = 4 cm

The printed area is 4x by 6x, so is 16 cm by 24 cm. With the margins added, the smallest poster will be ...

24 cm by 36 cm

_____

Comment on margins

It should be obvious that if both side margins are 4 cm, then the width of the poster is 8 cm more than the printed width. Similarly, the 6 cm top and bottom margins make the height of the poster 12 cm more than the height of the printed area.

_____

Alternate solution

Let w represent the width of the printed area. Then the printed height is 384/w, and the total poster area is ...

A = (w+8)(384/w +12) = 384 +12w +3072/w +96

Differentiating with respect to w gives ...

A' = 12 -3072/w^2

Setting this to zero and solving for w gives ...

w = √(3072/12) = 16 . . . . matches above solution.

Generic solution

If we let s and t represent the side and top margins, and we use "a" for the printed area, then the above equation becomes the symbolic equation ...

A = (w +s)(a/w +t)

A' = t - sa/w^2