The probable genotype of the IV-3 with the perspective of autosomal inheritance will be A because he does not have condition A. Therefore both parents must be in condition A.
The probable genotype of IV-3 with the perspective of set=linked inheritance will be BbY this is because he has B condition. Therefore the mothers' genotype must be XBXb and the father's genotype must be XBY.
The probability of IV-4 having condition A is 1/36
Meiosis is a type of cell division that reduces the number of chromosomes in the parent cell by half and produces four gamete cells. This process is required to produce egg and sperm cells for sexual reproduction. During reproduction, when the sperm and egg unit to form single cell for sexual reproduction. During reproduction, when the sperm and egg unit to form a single cell, the number of chromosome is restored in the offspring.
Meiosis begins with a parent cell that is diploid, meaning it has two copies of each chromosome. The parent cell undergoes one round of DNA replication followed by two separate cycles of nuclear division. The process results in four daughter cells that are haploid, which means they contain half the number of chromosomes of the diploid parent cell.
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duck such duck arm offend Karyn Lascaux jab
I would say the 2nd one It helps growth and repair of cells of orgasms
But your school would probably say the 3rd one It helps remove toxins from the body to maintain homeostasis
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Its 26 I'd assume sorry if I'm wrong it was kind of hard to read the question.