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omeli [17]
3 years ago
11

What is the slope of this graph? −14 4 14 −4 Number graph ranging from negative 10 to 10 on both the x and y axis. A line passes

through the point begin ordered pair 1 comma negative 2 end ordered pair and the point begin ordered pair 0 comma 2 end ordered pair
Mathematics
2 answers:
spin [16.1K]3 years ago
7 0

The slope of this graph is - 4

Step-by-step explanation:

The slope of a line is m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} , where

  • (x_{1},y_{1}) and (x_{2},y_{2}) are two points on the line
  • The slope of a horizontal line is zero
  • The slope of a vertical line is undefined

∵ The graph is a line

∵ The line passes through points (1 , -2) and (0 , 2)

∴ x_{1} = 1 and x_{2} = 0

∴ y_{1} = -2 and y_{2} = 2

- Substitute these values in the rule below

∵ m=\frac{y_{2}-y_{1}}{x_{2}-x_{2}}

∴ m=\frac{2--2}{0-1}=\frac{4}{-1}

∴ m = - 4

The slope of this graph is - 4

Learn more:

You can learn more about the slope of a line in brainly.com/question/4152194

#LearnwithBrainly

Leya [2.2K]3 years ago
3 0

Answer:

-4

Step-by-step explanation:

i took the test

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6.25+6.5=12.75

20-12.75=7.25

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A small tree is 80 cm tall.
ruslelena [56]
1.2 meters = 120 centimeters
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7 0
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Noah has just purchased a previously owned home. he put $5,000 towards a down payment and took out a $65,000 mortgage. noah know
cricket20 [7]
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5 0
1 year ago
Help me with this question please
docker41 [41]

7x/x-4 * x/x+7

mutiply the numerators together

(7x)(x)= 7x^ 2

mutiply the denominators together

(x-4)(x+7)

(x)(x)(7)(x)= x^2+7x

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x^2+7x-4x-28

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Answer:

7x^2/x^ 2+3x-28

6 0
3 years ago
Evaluate the expression and write your answer in the form a + bi. 1) (2-6i)+(4+2i)2) (6+5i)(9-2i)3) 2/(3-9i)4) (3 − 5i)(7 − 2i)
laiz [17]

Answer:

Step-by-step explanation:

Given the following complex numbers, we are to expressed them in the form of a+bi where a is the real part and b is the imaginary part of the complex number.

1) (2-6i)+(4+2i)

open the parenthesis

= 2-6i+4+2i

collect like terms

= 2+4-6i+2i

= 6-4i

2)  (6+5i)(9-2i)

= 6(9)-6(2i)+9(5i)-5i(2i)

= 54-12i+45i-10i²

= 54+33i-10i²

In complex number i² = -1

= 54+33i-10(-1)

= 54+33i+10

= 54+10+33i

= 64+33i

3) For the complex number 2/(3-9i), we will rationalize by multiplying by the conjugate of the denominator i.e 3+9i

= 2/3-9i*3+9i/3+9i

=2(3+9i)/(3-9i)(3+9i)

= 6+18i/9-27i+27i-81i²

= 6+18i/9-81(-1)

= 6+18i/9+81

= 6+18i/90

= 6/90 + 18i/90

= 1/15+1/5 i

4) For (3 − 5i)(7 − 2i)

open the parenthesis

= 3(7)-3(2i)-7(5i)-5i(-2i)

= 21-6i-35i+10i²

= 21-6i-35i+10(-1)

= 21-41i-10

= 11-41i

4 0
3 years ago
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