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3 years ago

Factor completely 3x − 12. 3(x − 4) 3(x + 4) 3x(−12) Prime

Mathematics

2 answers:

joja [24]3 years ago

8 0

The answer is 3x(-12) I 'am 100% show..

Daniel [21]3 years ago

3 0

Answer:

the answer is 3x(-12)

Step-by-step explanation:

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What is the slope no games please i will report!

NNADVOKAT [17]

Here the slope is 2/6

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3 years ago

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in the town of pleasant hill there is an average of 16 sunny days each month. write an expression to represent the approximate n

denis23 [38]

32 divided by 2 would equal 16 sunny days.

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3 years ago

An object has been thrown straight up into the air. The formula h = vt - 16t^2 gives the height of the object above the ground a

Oxana [17]

Answer:

8 seconds.

Step-by-step explanation:

To solve this question, we need to find the time, $t$ , when $h = 0$ , that is, when the height of the object above the ground is 0 feet.

Substituting $v = 128$ feet per second and $h = 0$ gives the quadratic:

$0 = 128t - 16t^{2}$

Since 128 is divisible by 16, it can be reduced to $0 = 16(8t - t^{2})$ .

We must now solve for $t$ .

We can easily see that one answer to the equation is 0,

$8(0) - (0)^{2} = 0$ (we need not concern ourselves with the 16 outside of the parenthesis as in the equation above, since 16 multiplied by 0 is 0). However this is the time the object is released into the air.

The second answer, $t = 8$ is also easy to see by inspection:

$8(8) - (8)^{2} = 0$ .

Therefore the object lands 8 seconds after it is thrown.

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3 years ago

Two streams flow into a reservoir. Let X and Y be two continuous random variables representing the flow of each stream with join

zlopas [31]

Answer:

c = 0.165

Step-by-step explanation:

Given:

f(x, y) = cx y(1 + y) for 0 ≤ x ≤ 3 and 0 ≤ y ≤ 3,

f(x, y) = 0 otherwise.

Required:

The value of c

To find the value of c, we make use of the property of a joint probability distribution function which states that

$\int\limits^a_b \int\limits^a_b {f(x,y)} \, dy \, dx = 1$

where a and b represent -infinity to +infinity (in other words, the bound of the distribution)

By substituting cx y(1 + y) for f(x, y) and replacing a and b with their respective values, we have

$\int\limits^3_0 \int\limits^3_0 {cxy(1+y)} \, dy \, dx = 1$

Since c is a constant, we can bring it out of the integral sign; to give us

$c\int\limits^3_0 \int\limits^3_0 {xy(1+y)} \, dy \, dx = 1$

Open the bracket

$c\int\limits^3_0 \int\limits^3_0 {xy+xy^{2} } \, dy \, dx = 1$

Integrate with respect to y

$c\int\limits^3_0 {\frac{xy^{2}}{2} +\frac{xy^{3}}{3} } \, dx (0,3}) = 1$

Substitute 0 and 3 for y

$c\int\limits^3_0 {(\frac{x* 3^{2}}{2} +\frac{x * 3^{3}}{3} ) - (\frac{x* 0^{2}}{2} +\frac{x * 0^{3}}{3})} \, dx = 1$

$c\int\limits^3_0 {(\frac{x* 9}{2} +\frac{x * 27}{3} ) - (0 +0) \, dx = 1$

$c\int\limits^3_0 {(\frac{9x}{2} +\frac{27x}{3} ) \, dx = 1$

Add fraction

$c\int\limits^3_0 {(\frac{27x + 54x}{6}) \, dx = 1$

$c\int\limits^3_0 {\frac{81x}{6} \, dx = 1$

Rewrite;

$c\int\limits^3_0 (81x * \frac{1}{6}) \, dx = 1$

The $\frac{1}{6}$ is a constant, so it can be removed from the integral sign to give

$c * \frac{1}{6}\int\limits^3_0 (81x ) \, dx = 1$

$\frac{c}{6}\int\limits^3_0 (81x ) \, dx = 1$

Integrate with respect to x

$\frac{c}{6} * \frac{81x^{2}}{2} (0,3) = 1$

Substitute 0 and 3 for x

$\frac{c}{6} * \frac{81 * 3^{2} - 81 * 0^{2}}{2} = 1$

$\frac{c}{6} * \frac{81 * 9 - 0}{2} = 1$

$\frac{c}{6} * \frac{729}{2} = 1$

$\frac{729c}{12} = 1$

Multiply both sides by $\frac{12}{729}$

$c = \frac{12}{729}$

$c = 0.0165 (Approximately)$

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3 years ago

Which rule describes the composition of transformations that maps ΔJKL to ΔJ"K"L"?

GarryVolchara [31]

Answer:

gj got the answer lol

Step-by-step explanation:

The rule for counter-clockwise (ccw) rotation is (x,y) change to (-y,x). Lmk if you're still stumped :D

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3 years ago