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expeople1 [14]
4 years ago
6

"Tongue Piercing May Speed Tooth Loss, Researchers Say" is the headline of an article. The article describes a study of 51 young

adults with pierced tongues. The researchers found receding gums, which can lead to tooth loss, in 19 of the participants. (a) Construct a 95% confidence interval for the proportion of young adults with pierced tongues who have receding gums. (Round your answers to three decimal places.) ( .138 Incorrect: Your answer is incorrect. , .503 Incorrect: Your answer is incorrect. )
Mathematics
1 answer:
Paul [167]4 years ago
3 0

Answer:

The 95% confidence interval for the proportion of young adults with pierced tongues who have receding gums is (0.24, 0.506).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 51, \pi = \frac{19}{51} = 0.373

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.373 - 1.96\sqrt{\frac{0.373*0.627}{51}} = 0.24

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.373 + 1.96\sqrt{\frac{0.373*0.627}{51}} = 0.506

The 95% confidence interval for the proportion of young adults with pierced tongues who have receding gums is (0.24, 0.506).

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Solve 8-2ab (a=2, b=3)
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What is the solution of log2x + 6 144 = 2?
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2x+6 is the base

Then the equation is logarithm of 144 on basis 2x + 6 = 2

Then [2x + 6]^2 = 144

Now expand the square binomial

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3 years ago
Using the work I’ve done so far as reference, show that neither triangle is a vector translation of the other. Draw a diagram.
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At Pike Place Fish Market in Seattle, customers can purchase a variety of different types of seafood. One type of seafood sold a
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Answer:

z=1.28

And if we solve for a we got

a=3.6 +1.28*0.8=4.624

So the value of height that separates the bottom 90% of data from the top 10% is 4.624.

So then the best answer for this case would be:

 C. 4.64

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

X \sim N(3.6,0.8)  

Where \mu=3.6 and \sigma=0.8

For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.1   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.9 of the area on the left and 0.1 of the area on the right it's z=1.28. On this case P(Z<1.28)=0.9 and P(z>1.28)=0.1

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=1.28

And if we solve for a we got

a=3.6 +1.28*0.8=4.624

So the value of height that separates the bottom 90% of data from the top 10% is 4.624.

So then the best answer for this case would be:

 C. 4.64

8 0
3 years ago
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