A. the answer is the first one
The required solution is ∠RQT = 202° and ∠QTS = 51°
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<h3>What is a cyclic quadrilateral?</h3>
A cyclic quadrilateral is a quadrilateral which has all its four vertices lying on a circle. It is also called as inscribed quadrilateral.
Its main property is that the sum of opposite angles of inscribed quadrilateral is always 180 degrees.
Now, the given circle has a cyclic quadrilateral QRST in which it is given that ∠RQT = 202° and ∠QRS = 129°
Since,sum of the opposite angles of a cyclic quadrilateral = 180°
⇒∠QTS + ∠QRS = 180°
⇒ ∠QTS + ∠129° = 180°
⇒ ∠QTS = 180° - ∠129°
⇒ ∠QTS = 51°
Hence,the requires angles are ∠RQT = 202° and ∠QTS = 51°.
More about cyclic quadrilateral :
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Answer:
2
Step-by-step explanation:
Answer:
Step-by-step explanation:
4x² + 20x + 25 = (2x)² + 2* 2x *5 + 5²
{Compare with a² + 2ab + b² = (a+ b)²}
= (2x + 5)²
= (2x +5)*(2x+5)
Side of the square = 2x+ 5
D=m-7
d+m=25
m-7+m=25
2m-7=25
2m=32
m=16
d=16-7
d=9
don is 9
