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Based on the given molecular formula, the molar mass of ethylene glycol is 62 g/mol. We solve for the number of moles of the solute,
n = (7.1 kg)(1000 g/ 1 kg) / 62g/mol = 114.52 mol
Then, we divide this value by the given mass of the water in kg
m = (114.52 mol) / 1.2 kg = 95.43 m
Thus, the molality of the substance is approximately equal to 95.43 m.
Answer:
3.88kg
Explanation:
weight=mass_of_body(m) x acceleration_due_to_gravity(g)
The weight is given and acceleration is also give
For mass divide the weight by acceleration.
Answer:
0.05 M
Explanation:
First we <u>convert 12 g of NaHSO₄ into moles</u>, using the <em>given molar mass</em>:
- 12 g NaHSO₄ ÷ 120.1 g/mol = 0.10 mol NaHSO₄
We can now <u>calculate the molarity of the resulting solution</u>, using the <em>calculated number of moles and the given volume</em>:
- Molarity = moles / liters
- Molarity = 0.10 mol / 2.00 L = 0.05 M
