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Elis [28]
3 years ago
9

Which is NOT an example of a pure substance?

Chemistry
1 answer:
ohaa [14]3 years ago
8 0
B c and d are not pure substances.
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How many grams of water are produced when 2.50 mol oxygen reacts with hydrogen?
natali 33 [55]
I think the answer is D
4 0
3 years ago
What is hydrogen bonding
yKpoI14uk [10]

Answer:

a weak bond between two molecules resulting from an electrostatic attraction between a proton in one molecule and an electronegative atom in the other.

Explanation:

For example, in water molecules (H2O), hydrogen is covalently bonded to the more electronegative oxygen atom. Therefore, hydrogen bonding arises in water molecules due to the dipole-dipole interactions between the hydrogen atom of one water molecule and the oxygen atom of another H2O molecule.

4 0
3 years ago
Give the name and formula of the compound formed from the following elements:<br> (b) ₃₀L and ₁₆M
madam [21]

When sulfur reacts with zinc metal is forms a compound known as zinc sulfide.

<h3>Name of the elements</h3>

The names of the elements that make up the compound will be determined from the atomic mass of the elements.

<h3>Which element has atomic number 30</h3>

The element that atomic number of 30 is zinc and it has oxidation number of +2.

<h3>Which element has atomic number 16</h3>

The element that atomic number of 16 is sulfur and it has oxidation number of -2.

<h3>Chemical reaction between sulfur and zinc metal</h3>

Zn²⁺ + S²⁻  --------> ZnS

Thus, when sulfur reacts with zinc metal is forms a compound known as zinc sulfide.

Learn more about zinc sulfide here: brainly.com/question/20806552

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8 0
1 year ago
When the following oxidation–reduction reaction in acidic solution is balanced, what is the lowest whole-number coefficient for
Svet_ta [14]

Answer:

c. 8, product side

Explanation:

In order to balance a redox reaction we use the ion-electron method, which has the following steps:

Step 1: identify oxidation and reduction half-reaction.

Oxidation: MnO₄⁻(aq) → Mn²⁺(aq)

Reduction: Br⁻(aq) → Br₂(l)

Step 2: perform the mass balance adding H⁺ and H₂O where necessary

8 H⁺(aq) + MnO₄⁻(aq) → Mn²⁺(aq) + 4 H₂O(l)

2 Br⁻(aq) → Br₂(l)

Step 3: perform the electrical balance adding electrons where necessary.

8 H⁺(aq) + MnO₄⁻(aq) + 5 e⁻ → Mn²⁺(aq) + 4 H₂O(l)

2 Br⁻(aq) → Br₂(l) + 2 e⁻

Step 4: multiply both half-reactions by numbers that secure that the number of electrons gained and lost are the same.

2 × (8 H⁺(aq) + MnO₄⁻(aq) + 5 e⁻ → Mn²⁺(aq) + 4 H₂O(l))

5 × (2 Br⁻(aq) → Br₂(l) + 2 e⁻)

Step 5: add both half-reactions side to side.

16 H⁺(aq) + 2 MnO₄⁻(aq) + 10 e⁻ + 10 Br⁻(aq) → 2 Mn²⁺(aq) + 8 H₂O(l) + 5 Br₂(l) + 10 e⁻

16 H⁺(aq) + 2 MnO₄⁻(aq) + 10 Br⁻(aq) → 2 Mn²⁺(aq) + 8 H₂O(l) + 5 Br₂(l)

3 0
3 years ago
Which of the following equations does not demonstrate the law of conservation of mass
tia_tia [17]
The answer is c :) i hope its the right answer
8 0
3 years ago
Read 2 more answers
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