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dimulka [17.4K]
3 years ago
11

A store sells rwo different types of coffee. Coffee a costs $7 per pound and coffee b costs $5 per pound. Amy bought 7 pounds of

coffee and spent a total of $41. How many pounds of each type of coffee did she buy?
Mathematics
1 answer:
Dovator [93]3 years ago
5 0

Answer:

A;3  B;4

Step-by-step explanation:

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9x-10 = 3x+ 2<br>What is the solution to the equation?<br>-2.<br>-1<br>1<br>2​
LuckyWell [14K]

Answer:

2

Step-by-step explanation:

6x = 12

Get x by itself.

4 0
3 years ago
The number of field mice found in a wheat field follows a Poission process. If the average number of field mice in a 5-acre whea
nika2105 [10]

Answer:

a) 56.97% probability that fewer than 3 field mice are found on a given acre.

b) 41.90% probability that in 2 of the next 3 acres inspected, fewer than 3 field mice are found on each acre.

Step-by-step explanation:

To solve this question, we use the Poisson probability distribution and the binomial probability distribution.

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given time interval.

Binomial distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

If the average number of field mice in a 5-acre wheat field is estimated to be 12.

Find the probability that

(a) fewer than 3 field mice are found on a given acre.

5 acres have a mean of 12. For one acre

\mu = \frac{12}{5} = 2.4

This probability is

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)

In which

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-2.4}*(2.4)^{0}}{(0)!} = 0.0907

P(X = 1) = \frac{e^{-2.4}*(2.4)^{1}}{(1)!} = 0.2177

P(X = 2) = \frac{e^{-2.4}*(2.4)^{2}}{(2)!} = 0.2613

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0907 + 0.2177 + 0.2613 = 0.5697

56.97% probability that fewer than 3 field mice are found on a given acre.

(b) in 2 of the next 3 acres inspected, fewer than 3 field mice are found on each acre.

Here we use the binomial probability distribution.

56.97% probability that fewer than 3 field mice are found on a given acre, which means that p = 0.5697

This probability is P(X = 2) when n = 3.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{3,2}.(0.5697)^{2}.(0.4303)^{1} = 0.4190

41.90% probability that in 2 of the next 3 acres inspected, fewer than 3 field mice are found on each acre.

8 0
3 years ago
What is -32(-5.6)(4) Please help I'm confused
belka [17]

Answer:

717.8 inches

Step-by-step explanation:

4 0
2 years ago
What is a solution set for xsquared+ 3X-4=6
qaws [65]
Xsquared+3x-4=6
xsquared+3x-10=0
(x+5)(x-2)=0
x=2,-5
7 0
3 years ago
What’s is the greatest number that can be made using the numbers 5, 3, 1, 4, 7
umka21 [38]
Hey there,

Answer: 75,431

Hope this helps :D

~Top♥
6 0
3 years ago
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