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masya89 [10]
2 years ago
14

What is the value of x? Enter your answer in the box. x =

Mathematics
1 answer:
d1i1m1o1n [39]2 years ago
6 0

Answer:

x=20

Step-by-step explanation:

We can use similar triangle to find x.  Put the smaller triangle over the larger triangle.

11             10

-------- = ----------

121+11       10 +5x+10

Combine like terms

11             10

-------- = ----------

132       20+5x

Using cross products

11 (20+5x) = 132*10

Distribute

220 +55x = 1320

Subtract 220 from each side

220-220 +55x = 1320-220

55x = 1100

Divide by 55

55x/55= 1100/55

x =20



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-6/7p+1/7 um Idk what you wanted me to do but I added -4/7p with -2/7p
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A newly established clothing shop analyzed their monthly profit compared to the amount spent on advertising each month. The foll
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The maximum profit is the highest point on the curve at (3, 45), and since the y-value is the profit in hundreds of dollars, the maximum profit is $4500.
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Need pre-cal help. Will mark best answer brainliest
OlgaM077 [116]

so, let's keep in mind that

\bf \begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}

so let's make a quick table of those solutions, say A, B, C solutions with x,y,z liters of acid, with an acidity of 0.25, 0.40 and 0.60 respectively.


\bf \begin{array}{lcccl} &\stackrel{solution}{quantity}&\stackrel{\textit{\% of }}{amount}&\stackrel{\textit{liters of }}{amount}\\ \cline{2-4}&\\ A&x&0.25&0.25x\\ B&y&0.40&0.4y\\ C&z&0.60&0.6z\\ \cline{2-4}&\\ mixture&78&0.45&35.1 \end{array} \\\\\\ \begin{cases} x+y+z=78\\ 0.25x+0.4y+0.6z=35.1 \end{cases}


we know she's using "z" liters and those are 3 times as much as "y" liters, so z = 3y.


\bf \begin{cases} x+y+3y=78\\ x+4y=78\\[-0.5em] \hrulefill\\ 0.25x+0.4y+0.6(3y)=35.1\\ 0.25x+0.4y=1.8y=35.1\\ 0.25x+2.2y=35.1 \end{cases}\implies \begin{cases} x+4y=78\\\\ 0.25x+2.2y=35.1 \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ x+4y=78\implies \boxed{x}=78-4y \\\\\\ \stackrel{\textit{using substitution on the 2nd equation}}{0.25\left( \boxed{78-4y} \right)+2.2y=35.1}\implies 19.5-y+2.2y=35.1


\bf 1.2y=15.6\implies y=\cfrac{15.6}{1.2}\implies \blacktriangleright y=13 \blacktriangleleft \\\\\\ x=78-4y\implies x=78-4(13)\implies \blacktriangleright x=26 \blacktriangleleft \\\\\\ z=3y\implies z=3(13)\implies \blacktriangleright z=39 \blacktriangleleft \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill \stackrel{25\%}{26}\qquad \stackrel{40\%}{13}\qquad \stackrel{60\%}{39}~\hfill

5 0
2 years ago
Can someone help pls.
kap26 [50]

<em>My goodness, this is rather confusing in the way it is worded. Nevertheless, I will attempt to do what I can. Just please keep in mind that this is my own interpretation of the problem, and therefore could be... incorrect.</em>

<em>I think, to start out, we could set up the problem like so</em>

<em>15 + t ≥ 26</em>

<em>because t is not a set number. </em>

<em>Then all that is needed is to subtract 15 from both sides, and the equation becomes</em>

<em>t ≥ 11</em>

<em>So the resulting answer is t ≥ 11.</em>

<em />

<em>I hope that my interpretation helps.</em>

<em>-Toremi</em>

<em />

8 0
2 years ago
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Hey you ‼️ yeah I unfortunately need your help again these are hard:(
Helga [31]

Answer:

Step-by-step explanation:

The point of this question is to find out the point where two lines intersect. First we need to get the equation of those lines

Slope of line 1:

(Yb -Ya)/(Xb - Xa) =

(-10 - (-14))/(-1 - (-3)) =

4/2 =

2

Use that slope to find the Y-intercept of line 1

y = 2x + b

-14 = 2(-3) +b

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Therefore Line 1 is:

y = 2x - 8

Slope of line 2

(11 - 13)/(-1 - (-3)) =

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-1

Y-intercept of line 2

y = -x + b

13 = -(-3) +b

13 = 3 + b

10 = b

Therefore line 2 is

y = -x + 10

Now we have 2 equations to solve for the coordinates x and y

y = 2x - 8

y = -x + 10

Substitute y out in one of the equations

2x - 8 = -x + 10

3x = 18

x = 6

Plug x into one of the equations

y = 2(6) - 8

y = 12 - 8

y = 4

Therefore the solution is:

x=6, y=4

8 0
3 years ago
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