<h3>Procedural steps are: - </h3>
- On a small scale, the reaction is carried out by combining the alcohol, the haloalkane, and the phase transfer catalyst in a conical vial.
- To start the reaction, sodium hydoxide (base) is added.
- To prevent solvent evaporation, the reaction flask is covered and stirred during the reaction.
- TLC monitors the reaction's progress to ensure that no time is wasted.
- To remove any remaining water, the reaction solution is dried over calcium chloride.
- Column chromatography is used to purify the product, and evaporation is used to collect it.
<h3>What is Catalysis?</h3>
Catalysis is the process of boosting the pace of a chemical reaction by using a catalyst. Catalysts are not consumed in the reaction and so survive it.
To learn more about catalysis from the given link
brainly.com/question/1372992
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Answer:
4.74
Explanation:
It is possible to find pH of a buffer (The mixture of a weak acid: Acetic acid, with its conjugate base: Sodium acetate) using Henderson-Hasselbalch equation:
pH = pKa + log₁₀ [A⁻] / [HA]
<em>Where pKa is -log Ka of the weak acid, [A⁻] concentration of the conjugate base and [HA] concentration of the weak acid</em>
pKa of acetic acid is -log 1.8x10⁻⁵ = 4.74
The concentration of both, acetic acid and sodium acetate is 0.1M. Replacing in H-H equation:
pH = pKa + log₁₀ [A⁻] / [HA]
pH = 4.74 + log₁₀ [0.1] / [0.1]
pH = 4.74 + log₁₀ 1
<em>pH = 4.74</em>
Theoretical pH is 4.74
<em />
2Al + 6HCl ----> 2AlCl3 + 3H2
Answer:
1) 0 C2H4O2 + 0 O2 -> 0 CO2 + 0 H2O (balanced)
2) V2O5 + CaS -> CaO + V2S5
<em>just additional info: V2O5 </em><em>is</em><em> </em><em>divanadium</em><em> </em><em>pentaoxide</em>
LHS (Left hand side)
V: 2
O: 5
Ca: 1
S: 1 x 5 [to balance with the right hand side of the equation]
RHS (Right hand side)
V: 2
O: 1 x 5 [to balance with the left hand side of the equation]
Ca: 1
S: 5
When you balance any elements, you have to balance the whole chemical compound.
Thus,
V2O5 + <em><u>5</u></em> CaS -> <em><u>5</u> CaO</em> + V2S5
LHS CHECK:
V: 2
O: 5
Ca: 5
S: 5
RHS CHECK:
V: 2
O: 5
Ca: 5
S: 5
3) S8 + O2 -> SO2
LHS:
S: 8
O: 2
RHS:
S: 1 x 8 [to balance with LHS]
O: 2
When you balance any elements, you have to balance the whole chemical compound.
S8 + O2 -> <em><u>8</u></em><em><u> </u></em>SO2
When we add 8 to the RHS, it gives us 8S, 16 O.
In order to balance that into the RHS, I need to multiply the O2 by 8, which will give 8(O2) = 16 O particles.
Therefore, <em><u>S8</u></em><em><u> </u></em><em><u>+</u></em><em><u> </u></em><em><u>8</u></em><em><u> </u></em><em><u>O2</u></em><em><u> </u></em><em><u>-</u></em><em><u>></u></em><em><u> </u></em><em><u>8</u></em><em><u> </u></em><em><u>SO2</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>final</u></em><em><u> </u></em><em><u>answer</u></em><em><u> </u></em><em><u>for</u></em><em><u> </u></em><em><u>(</u></em><em><u>3</u></em><em><u>)</u></em><em><u>.</u></em>