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3 years ago

HELPP ILL GUVE YOU LOTS OF POINTS EVERYTHING U WANT I REALLY NEED HELP

Chemistry

1 answer:

Alja [10]3 years ago

7 0

Answer:

but what is your question? it's just like the moon going around earth while earth along with all the other planets revolve around the sun

Explanation:

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Explains how commercial land use negatively impacts watersheds?

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Polluted water. The growing crops and climate variability change. Basically the farming

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4 years ago

Two reasons why a scientist might want to study the DNA of strawberries?

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1.To discover the chromosomal state of the species in order to advance on Knowledge of the species Evolutionary process.
2. To form a hybrid of the species.

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3 years ago

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For the reaction ? Fe+? H2o ⇀↽? Fe3o4+? H2 , a maximum of how many grams of fe3o4 could be formed from 354 g of fe and 839 g of

Evgesh-ka [11]

The given reaction is:

3Fe + 4H2O → Fe3O4 + 4H2

Given:

Mass of Fe = 354 g

Mass of H2O = 839 g

Calculation:

Step 1 : Find the limiting reagent

Molar mass of Fe = 56 g/mol

Molar mass of H2O = 18 g/mol

# moles of Fe = mass of Fe/molar mass Fe = 354/56 = 6.321 moles

# moles of H2O = mass of h2O/molar mass of H2O = 839/18 = 46.611 moles

Since moles of Fe is less than H2O; Fe is the limiting reagent.

Step 2: Calculate moles of Fe3O4 formed

As per reaction stoichiometry:

3 moles of Fe form 1 mole of Fe3O4

Therefore, 6.321 moles of Fe = 6.321 * 1/ 3 = 2.107 moles of Fe3O4

Step 4: calculate the mass of Fe3O4 formed

Molar mass of Fe3O4 = 232 g/mol

# moles = 2.107 moles

Mass of Fe3O4 = moles * molar mass

= 2.107 moles * 232 g/mol = 488.8 g (489 g approx)

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3 years ago

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You're provided with a bottle labled [CoCl2.6H2O] = 0.056 M in 4.60 M HCl. You heat a small volume of the solution in a hot wate

sweet [91]

Answer: Equilibrium concentration of $[Cl^-]$ at $50^0C$ is 4.538 M

Explanation:

Initial concentration of $CoCl_2$ = 0.056 M

Initial concentration of $Cl^-$ = 4.60 M

The given balanced equilibrium reaction is,

$COCl_2+2Cl^-\rightleftharpoons [CoCl_4]^{2-}+6H_2O$

Initial conc. 0.056 M 4.60 M 0 M 0 M

At eqm. conc. (0.056-x) M (4.60-2x) M (x) M (6x) M

The expression for equilibrium constant for this reaction will be,

$K_c=\frac{[CoCl_4]^{2-}\times [H_2O]^6}{[CoCl_2]^2\times [Cl^-]^2}$

Given : equilibrium concentration of $[CoCl_4]^{2-}$ =x = 0.031 M

Concentration of $Cl^-$ = (4.60-2x) M = $(4.60-2\times 0.031)$ =4.538 M

Thus equilibrium concentration of $[Cl^-]$ at $50^0C$ is 4.538 M

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4 years ago

Cassady? you there ?

iren [92.7K]

Answer:

who da hell is cassady?

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3 years ago

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HELPP ILL GUVE YOU LOTS OF POINTS EVERYTHING U WANT I REALLY NEED HELP ​​

HELPP ILL GUVE YOU LOTS OF POINTS EVERYTHING U WANT I REALLY NEED HELP