It’s c had this problem last week
Answer:
The minimum amount of energy required to remove the most loosely bound electron of an isolated neutral gaseous atom or molecule. Pls mark as breinlest
Answer:
5.9 × 10^-6.
Explanation:
In the arrangements of crystal solids there is likely going to be an imperfection or defect and one of the defect or imperfections in the arrangements of solids is known as the Schottky defects. The Schottky defects is a kind of lattice arrangements imperfection that occurs when positively charged ions and negatively charged ions leave their position.
So, let us delve right into the solution of the question. We will be making use of the formula below;
Wb/ W = e^ - c/ 2kT.
Where Wb/ W= fraction of lattice sites, c= energy for defect formation = 1.86 eV, and T = temperature= 623° C= 896 k.
So, Wb/ W = e ^ -1.86/ (2 × 896 × 8.62 × 10^ -5).
Wb/ W= 0.000005896557435956372.
Wb/ W=5.9 × 10^-6.
