A snail can move 1/2 mile in 5 hours.How fast does a snail move in miles/hour

6 38/45 + 2 5/9 <br><br> Enter your answer in the box as a mixed number in simplest form.

Paul [167]

Answer:

9 2/5

Step-by-step explanation:

6 38/45 + 2 5/9

6 38/45 + 2 25/45 = 8 63/45 = 9 18/45 = 9 2/5

4 0

2 years ago

The difference of a number multiplied by 2 tens and 3 sevens is 119. What is the number?

Elan Coil [88]

Your question is not clearly stated. Do you mean the difference between 10 * 10 * x, and 7 * 7 * 7 *x ? Then the number is x = 119/243. That's about 0.48971... in decimal form.

It's confusing when you say the "difference of a number". Differences are BETWEEN two numbers. See what I mean?

4 0

3 years ago

Help with these two math questions please

Furkat [3]

Because the two triangles are similar, their angles will be the exact same.

Therefore, Angle B is 130 degrees

The answer is D.

There isn't a graph to look at for the second question so I can't help you on that one

3 0

3 years ago

Read 2 more answers

A medical researcher wondered if there is a significant difference between the mean birth weight of boy and girl babies. Random

Yuliya22 [10]

Answer:

b) independent samples t-test

$t=\frac{(5.92 -5.74)-(0)}{\sqrt{\frac{1.88^2}{5}}+\frac{1.81^2}{5}}=0.154$

$p_v =2*P(t_{8}>0.154) =0.881$

So with the p value obtained and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the mean of the group 1 (boys) is NOT significantly different than the mean for the group 2 (Girls).

Step-by-step explanation:

The system of hypothesis on this case are:

Null hypothesis: $\mu_1 = \mu_2$

Alternative hypothesis: $\mu_1 \neq \mu_2$

Or equivalently:

Null hypothesis: $\mu_1 - \mu_2 = 0$

Alternative hypothesis: $\mu_1 -\mu_2\neq 0$

Our notation on this case :

$n_1 =5$ represent the sample size for group 1

$n_2 =5$ represent the sample size for group 2

We can calculate the mean and deviation for eaach group with the following formulas:

$\bar X= \frac{\sum_{i=1}^n X_i}{n}$

$s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

$\bar X_1 =5.92$ represent the sample mean for the group 1

$\bar X_2 =5.74$ represent the sample mean for the group 2

$s_1=1.88$ represent the sample standard deviation for group 1

$s_2=1.81$ represent the sample standard deviation for group 2

If we see the alternative hypothesis we see that we are conducting a bilateral test and with independnet samples t test.

b) independent samples t-test

The statistic is given by this formula:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{\sqrt{\frac{s^2_1}{n_1}}+\frac{S^2_2}{n_2}}$

And now we can calculate the statistic:

$t=\frac{(5.92 -5.74)-(0)}{\sqrt{\frac{1.88^2}{5}}+\frac{1.81^2}{5}}=0.154$

The degrees of freedom are given by:

$df=5+5-2=8$

And now we can calculate the p value using the altenative hypothesis:

$p_v =2*P(t_{8}>0.154) =0.881$

So with the p value obtained and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the mean of the group 1 (boys) is NOT significantly different than the mean for the group 2 (Girls).

7 0

3 years ago

I wasn’t so sure on how to solve this, anyone mind helping me?

sweet-ann [11.9K]

Answer:

Rays: A, B, C, D - 4 rays for each.

Line segments: AB, BD, DC, CA.

7 0

2 years ago