Can someone help me pls

a bag contains 4 green marbles, 6 red marbles, 14 orange marbles, 5 brown marbles, and 8 blue marbles. you choose a marble, repl

Triss [41]

By what is P i assume you mean what is the probability.
Well probability is always the specific group divided by the total
To find the total add all the marbles together
4 + 6 + 14 + 5 +8 = 37
Before we move on notice the question says that the marble is replaced after being chosen meaning the total stays the same for every pick
Red Marbles Probability:
red marbles/ total
6/37 or if you divide it out 0.162
Blue Marbles Probability:
blue marbles/total
8/37 or 0.216

8 0

3 years ago

A 25% vinegar solution is combined with triple the amount of a 45% vinegar solution and a 5% vinegar solution resulting in 20 mi

Murrr4er [49]

Complete Question: A 25% vinegar solution is combined with triple the amount of a 45% vinegar solution and a 5% vinegar solution resulting in 20 milliliters of a 30% vinegar solution.

Write an equation that models this situation and explain what each part represents in the situation. Then solve the equation.

Step-by-step explanation:

let the volume of the 45% vinegar solution be x litres ,

the volume of the 25% vinegar solution be 3x

and the volume of the 5% vinegar solution be y

summation of all gives,

x+3x+y = 20

4x + y = 20

subtracting 4x from both sides to make y the subject of the equation, we have;

y = 20 - 4x

To the concentration:

substituting for the value of x and y into equation x + 3x + y = 20, we have,

.45x + .25(3x) + .05(20-4x) = .3(20)

multiplying through by 100 to make whole figures we have;

45x + 25(3x) + 5(20-4x) = 600

45x + 75x + 100 - 20x = 600

120x - 20x + 100 = 600

100x + 100 = 600

subtracting 100 from both sides, we have;

100x = 600 - 100

100x = 500

dividing both sides by 100,

x = 5.

7 0

3 years ago

If K(x) = |x-3| + x, find k(4)

swat32

Answer:

5

Step-by-step explanation:

First do substitution,

Which means |(4)-3|+4

Therefore 1+4=5

7 0

3 years ago

What is the radius of a circle whose equation is x^2 + y^2 + 8x - 6y + 21 =0

sveta [45]

Hello,

x^2+y^2+8x-6y+21=0

Rewritten in the form of a standard circle equation:

(x-(-4))^2+(y-3)^2=2^2

Therefore, the circle properties are:

(a,b)=(-4,3),r=2

The radius of the circle whose equation is <span>x^2 + y^2 + 8x - 6y + 21 =0 is 2.

Faith xoxo</span>

3 0

3 years ago

Read 2 more answers

Consider the function on the interval (0, 2π). f(x) = sin x + cos x (a) Find the open intervals on which the function is increas

Annette [7]

Answer:Increasing in x∈(0,π/4)∪(5π/4,2π) decreasing in(π/4,5π/4)

Step-by-step explanation:

given f(x) = sin(x) + cos(x)

f(x) can be rewritten as $\sqrt{2} [\frac{sin(x)}{\sqrt{2} }+\frac{cos(x)}{\sqrt{2} } ]..................(a)\\\\\ \frac{1}{\sqrt{2} } = cos(45) = sin(45)\\\\$

Using these result in equation a we get

f(x) = $\sqrt{2} [ cos(45)sin(x)+sin(45)cos(x)]\\\\= \sqrt{2} [sin(45+x)]..........(b)$

Now we know that for derivative with respect to dependent variable is positive for an increasing function

Differentiating b on both sides with respect to x we get

f '(x) = $f '(x)=\sqrt{2} \frac{dsin(45+x)}{dx}\\ \\f'(x)=\sqrt{2} cos(45+x)\\\\f'(x)>0=>\sqrt{2} cos(45+x)>0$

where x∈(0,2π)

we know that cox(x) > 0 for x∈[0,π/2]∪[3π/2,2π]

Thus for cos(π/4+x)>0 we should have

1) π/4 + x < π/2 => x<π/4 => x∈[0,π/4]

2) π/4 + x > 3π/2 => x > 5π/4 => x∈[5π/4,2π]

from conditions 1 and 2 we have x∈(0,π/4)∪(5π/4,2π)

Thus the function is decreasing in x∈(π/4,5π/4)

5 0

3 years ago