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2 years ago

Can someone help me pls

Mathematics

1 answer:

Arturiano [62]2 years ago

8 0

Answer:

i got u

Step-by-step explanation:

i got u

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the cost to rent a photo booth for a party is a one time fee of $25 plus $30 per hour the photo booth is running. If the photo b

sdas [7]

Answer: 25+30h=180

Step-by-step explanation:

The one time fee is 25 and plus the $30 per hour so you have 25 plus $30 h= hour equals 180. I took the a test and got it right btw.

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2 years ago

The Double Scoop ice cream store ordered 100 pints of vanilla ice cream. How many quarts of ice cream did the store order?

schepotkina [342]

Answer:

50 quarts.

Step-by-step explanation:

One pint is half a quart.

100/2 = 50

100 pints should be 50 quarts.

Hope this helps!

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2 years ago

What is a fraction <br> just to know

maw [93]

Answer:

Step-by-step explanation:A fraction is like a pizza you got the pizza into three force you shading three of them that’s a fraction

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3 years ago

Evaluate Functions<br> Given f(x) = 2x + 6 and g(x) = 5x - 1<br> Evaluate f(-2)

ZanzabumX [31]

Answer:

f(-2) = -4x + 6

Step-by-step explanation:

f(x) = 2x + 6

f(-2) = -2(2x) + 6

f(-2) = -4x + 6

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2 years ago

Read 2 more answers

Use implicit differentiation to find an equation of the tangent line to the curve at the given point. x2/3 + y2/3 = 4 (−3 3 , 1)

vovikov84 [41]

Answer with Step-by-step explanation:

We are given that an equation of curve

$x^{\frac{2}{3}}+y^{\frac{2}{3}}=4$

We have to find the equation of tangent line to the given curve at point $(-3\sqrt3,1)$

By using implicit differentiation, differentiate w.r.t x

$\frac{2}{3}x^{-\frac{1}{3}}+\frac{2}{3}y^{-\frac{1}{3}}\frac{dy}{dx}=0$

Using formula : $\frac{dx^n}{dx}=nx^{n-1}$

$\frac{2}{3}y^{-\frac{1}{3}}\frac{dy}{dx}=-\frac{2}{3}x^{-\frac{1}{3}}$

$\frac{dy}{dx}=\frac{-\frac{2}{3}x^{-\frac{1}{3}}}{\frac{2}{3}y^{-\frac{1}{3}}}$

$\frac{dy}{dx}=-\frac{x^{-\frac{1}{3}}}{y^{-\frac{1}{3}}}$

Substitute the value x= $-3\sqrt3,y=1$

Then, we get

$\frac{dy}{dx}=-\frac{(-3\sqrt3)^{-\frac{1}{3}}}{1}$

$\frac{dy}{dx}=-(-3^{\frac{3}{2}})^{-\frac{1}{3}}=-\frac{1}{-(3)^{\frac{3}{2}\times \frac{1}{3}}}=\frac{1}{\sqrt3}$

Slope of tangent=m= $\frac{1}{\sqrt3}$

Equation of tangent line with slope m and passing through the point $(x_1,y_1)$ is given by

$y-y_1=m(x-x_1)$

Substitute the values then we get

The equation of tangent line is given by

$y-1=\frac{1}{\sqrt3}(x+3\sqrt3)$

$y-1=\frac{x}{\sqrt3}+3$

$y=\frac{x}{\sqrt3}+3+1$

$y=\frac{x}{\sqrt3}+4$

This is required equation of tangent line to the given curve at given point.

8 0

3 years ago