Can someone help on this I'm really stuck
1 answer:
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A single photon carries an energy equal to
where h is the Planck's constant and f is the frequency of the photon.
This means that the higher the frequency of the light, the higher the energy. Among the 5 different options mentioned by the problem, the light with highest frequency is ultraviolet, which has frequencies in the range [3-30] PHz, while visible light (red, blue, green) and infrared have lower frequency, so ultraviolet light has the highest energy per photon.
where h is the Planck's constant and f is the frequency of the photon.
This means that the higher the frequency of the light, the higher the energy. Among the 5 different options mentioned by the problem, the light with highest frequency is ultraviolet, which has frequencies in the range [3-30] PHz, while visible light (red, blue, green) and infrared have lower frequency, so ultraviolet light has the highest energy per photon.
Answer:
La aceleración del automovil antes de deternerse es -5.5 m/s².
Explanation:
Podemos encontar la aceleración del auto usando la siguiente ecuación:
En donde:
: es la velocidad final = 0 (se detiene)
: es la velocidad inicial
a: es la aceleración=?
t: es el tiempo = 4.0 s
Primero debemos encontrar la velocidad inicial, para ellos usaremos la siguiente ecuación de moviemiento rectilíneo uniforme:
Ahora, la aceleración es:
El signo negativo se debe a que el auto está desacelerando.
Entonces, la aceleración del automovil antes de deternerse es -5.5 m/s².
Espero que te sea de utilidad!