A bell or a siren or a ring in somewhere
Answer:
Explanation:
given,
tuning fork vibration = 508 Hz
accelerates = 9.80 m/s²
speed of sound = 343 m/s
observed frequency = 490 Hz


![v_s = v[\dfrac{f_s}{f_o}-1]](https://tex.z-dn.net/?f=v_s%20%3D%20v%5B%5Cdfrac%7Bf_s%7D%7Bf_o%7D-1%5D)
![= 343[\dfrac{508}{490}-1]](https://tex.z-dn.net/?f=%3D%20343%5B%5Cdfrac%7B508%7D%7B490%7D-1%5D)

distance the tunning fork has fallen


=8.1 m
now, time required for the observed will be

now, for the distance calculation


=0.293 m
total distance
= 8.1 + 0.293 = 8.392 m
Answer: If it does not support the hypothesis, you may choose to change the hypothesis or write a new one based on what was learned during the experiment.
Hypothesize a new answer to the question and a new way to test it.
Explanation:
Answer:
The diagram represents two charges, q1 and q2, separated by a distance d. Which change would produce the greatest increase in the electrical force between the two charges? *
Explanation:
doubling charge q1, only
Answer:
Explanation:
Given that
The mass of the body is 0.04kg
M=0.04kg
The radius of the paths is 0.6m
r=0.6m
The normal force exerted at A is 3.9N
Fa=3.9N
The normal force exerted at B is 0.69N
Fb=0.69N
Then work done by friction from point A to B will be the change in K.E
W=∆K.E+P.E
So we need to know the velocity at both point A and B
Then since the centripetal force is given as
Ft=mv²/r
Then,
For point A
Fa=mv²/r
3.9=0.04v²/0.6
3.9=0.0667v²
v²=3.9/0.0667
v²=58.5
v=√58.5
v=7.65m/s
Va=7.65m/s
Now at point B
Fb=mv²/r
0.69=0.04v²/0.6
0.69=0.0667v²
v²=0.69/0.0667
v²=10.35
v=√10.35
v=3.22m/s
Vb=3.22m/s
Then, the work done is
W=∆K.E+P.E
P.E is given as mgh
The height will be 2R =1.2m
P.E=mgh
P.E=0.04×9.81×1.2
P.E=0.471J
Final kinetic energy at B minus initial kinetic energy at A
W=K.Eb-K.Ea
K.E is given as 1/2mv²
W=1/2m(Vb²-Va²) +P.E
W=0.5×0.04(3.22²-7.65²) +0.471
W=0.5×0.04×(-48.1541) +0.471
W=-0.96+0.471
W=-0.49J
work was done on the block by friction during the motion of the block from point A to point B is 0.49J.
Friction opposes motions and that is why the work done is negative