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iren2701 [21]
3 years ago
13

Un automóvil deportivo se mueve a rapidez constante viaja 110m en 5.0s si entonces frena y llega a detenerse en 4.0s ¿Cuál es su

aceleración en m/s²?
Physics
1 answer:
noname [10]3 years ago
3 0

Answer:

La aceleración del automovil antes de deternerse es -5.5 m/s².

Explanation:

Podemos encontar la aceleración del auto usando la siguiente ecuación:

v_{f} = v_{0} + at

En donde:

v_{f}: es la velocidad final = 0 (se detiene)

v_{f}: es la velocidad inicial

a: es la aceleración=?

t: es el tiempo = 4.0 s

Primero debemos encontrar la velocidad inicial, para ellos usaremos la siguiente ecuación de moviemiento rectilíneo uniforme:

v_{0} = \frac{x}{t} = \frac{110 m}{5.0 s} = 22 m/s

Ahora, la aceleración es:

a = \frac{v_{f} - v_{0}}{t} = \frac{0 - 22 m/s}{4.0 s} = -5.5 m/s^{2}

El signo negativo se debe a que el auto está desacelerando.

Entonces, la aceleración del automovil antes de deternerse es -5.5 m/s².

Espero que te sea de utilidad!                          

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Qué es el espectro electromagnético
Lynna [10]
Es el conjunto de longitudes de onda de todas las radiaciones electromagnéticas
5 0
3 years ago
Which of the following statements about the conservation of momentum is not correct? Momentum is conserved for a system of objec
Olin [163]

Answer:

wrong statement :  Momentum is not conserved for a system of objects in a head-on collision.

Explanation:

In a head on collision of two objects , two equal and opposite forces are created at the point of collision . These two forces create two impulses in opposite direction which results in equal and opposite changes in momentum in each of them . Hence net change in momentum is zero. In this way momentum is conserved in head on collision of two objects.

3 0
4 years ago
A person kicks a 4.0-kilogram door with a 48-newton force causing the door to accelerate at 12 meters per second squared. What i
inna [77]

Answer:

-48 N

Explanation:

mass of door (m) = 4 kg

acceleration of the door = 12 m/s^{2}

force exerted by the person = 48 N

From Newton's third law of motion, action and reaction are equal but opposite. Therefore the force exerted on the door by the person which is 48 N will be the same as the force exerted on the person by the door but opposite in its direction, and this would be - 48 N

7 0
3 years ago
Over a span of 6.0 seconds, a car changes it's speed from 89 km/h to 37 km/h. What is its average acceleration in meters per sec
scoundrel [369]

Acceleration = (change in speed) / (time for the change)

change in speed = (speed at the end) - (speed at the beginning)

change in speed = (37 km/hr) - (89 km/hr) = -52 km/hr

Acceleration = (-52 km/hr) / (6 sec)

Acceleration = (-26/3) km/(hr·sec)

Units: (1/hr·sec) · (hr/3600 sec) = 1 / 3600 sec²

(-26/3) km/(hr·sec) = (-26/3) km/(3600 sec²)

= -26,000/(3 · 3600) m/s²

<em>Acceleration = -2.41 m/s²</em>

3 0
4 years ago
A man 2 m tall walks horizontally at a constant rate of 1 m/s toward the base of a tower 23 m tall. When the man is 10 m from th
Evgen [1.6K]

Answer:

\dfrac{d\theta}{dt}=0.038\ rad/s

Explanation:

Given that

\dfrac{dx}{dt}= -1\ m/s

From the diagram

tan\theta=\dfrac{21}{x}

By differentiating with time t

sec^2\theta \dfrac{d\theta}{dt}=-\dfrac{21}{x^2}\dfrac{dx}{dt}

When x= 10 m

tan\theta=\dfrac{21}{10}

θ = 64.53°

Now by putting the value in equation

sec^2\theta \dfrac{d\theta}{dt}=-\dfrac{21}{x^2}\dfrac{dx}{dt}

sec^264.53^{\circ} \dfrac{d\theta}{dt}=-\dfrac{21}{10^2}\times (-1)

\dfrac{d\theta}{dt}=0.038\ rad/s

Therefore rate of change in the angle is 0.038\ rad/s

8 0
3 years ago
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