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3 years ago

13

Un automóvil deportivo se mueve a rapidez constante viaja 110m en 5.0s si entonces frena y llega a detenerse en 4.0s ¿Cuál es su

aceleración en m/s²?

1 answer:

noname [10]3 years ago

3 0

Answer:

La aceleración del automovil antes de deternerse es -5.5 m/s².

Explanation:

Podemos encontar la aceleración del auto usando la siguiente ecuación:

$v_{f} = v_{0} + at$

En donde:

$v_{f}$ : es la velocidad final = 0 (se detiene)

$v_{f}$ : es la velocidad inicial

a: es la aceleración=?

t: es el tiempo = 4.0 s

Primero debemos encontrar la velocidad inicial, para ellos usaremos la siguiente ecuación de moviemiento rectilíneo uniforme:

$v_{0} = \frac{x}{t} = \frac{110 m}{5.0 s} = 22 m/s$

Ahora, la aceleración es:

$a = \frac{v_{f} - v_{0}}{t} = \frac{0 - 22 m/s}{4.0 s} = -5.5 m/s^{2}$

El signo negativo se debe a que el auto está desacelerando.

Entonces, la aceleración del automovil antes de deternerse es -5.5 m/s².

Espero que te sea de utilidad!

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In si units, the electric field in an electromagnetic wave is described by ey = 104 sin(1.40 107x − ωt). (a) find the amplitude

melamori03 [73]

Answers:
(a) $B_o = 0.3466$ μT
(b) $\lambda = 0.4488$ μm
(c) f = $6.68 * 10^{14}Hz$

Explanation:
Given electric field(in y direction) equation:
$E_y = 104sin(1.40 * 10^7 x -\omega t)$

(a) The amplitude of electric field is $E_o = 104$ . Hence

The amplitude of magnetic field oscillations is $B_o = \frac{E_o}{c}$
Where c = speed of light

Therefore,
$B_o = \frac{104}{3*10^8} = 0.3466$ μT (Where T is in seconds--signifies the oscillations)

(b) To find the wavelength use:
$\frac{2 \pi }{\lambda} = 1.40 * 10^7$
$\lambda = \frac{2 \pi}{1.40} * 10^{-7}$
$\lambda = 0.4488$ μm

(c) Since c = fλ
=> f = c/λ

Now plug-in the values
f = (3*10^8)/(0.4488*10^-6)
f = $6.68 * 10^{14}Hz$

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3 years ago

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The density of an object determines whether it will float or sink in another substance. An object will float if it is less dense than the liquid it is placed in. An object will sink if it is more dense than the liquid it is placed in.
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A glass bottle of soda is sealed with a screw cap. The absolute pressure of the carbon dioxide inside the bottle is 1.50 x 105 P

MArishka [77]

Answer:

$F \approx 19.5 N$

Explanation:

From the question we are told that:

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Where

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$P_r=0.487*10^5 pa$

Generally the equation for Force exerted by screw F is give as is mathematically given by

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2 years ago

A 70.0 kg astronaut is training for accelerations that he will experience upon reentry. He is placed in a centrifuge (r = 15.0 m

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Answer:

1.3823 rad/s

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2006.29095 N radially outward

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r = Radius = 15 m

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$\omega=13.2\times \dfrac{2\pi}{60}\\\Rightarrow \omega=1.3823\ rad/s$

Angular velocity is 1.3823 rad/s

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$v=r\omega\\\Rightarrow v=15\times 1.3823\\\Rightarrow v=20.7345\ m/s$

The linear velocity is 20.7345 m/s

Centripetal acceleration is given by

$a_c=r\omega^2\\\Rightarrow a_c=15\times 1.3823^2\\\Rightarrow a_c=28.66129935\ m/s^2$

The centripetal acceleration is 28.66129935 m/s²

Acceleration in terms of g

$\dfrac{a}{g}=\dfrac{28.66129935}{9.81}\\\Rightarrow a=2.92164g$

$a=2.92164g$

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$F_c=ma_c\\\Rightarrow F_c=70\times 28.66129935\\\Rightarrow F_c=2006.29095\ N$

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Answer:

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