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lord [1]
3 years ago
15

Which statement or phrase best describes the currently accepted model of the atom?

Physics
2 answers:
Anna [14]3 years ago
8 0

Answer:

i am pretty sure that it is 4

Viktor [21]3 years ago
6 0

Answer:

4

Explanation:

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Four metals were kept in contact with each other. The table below shows the initial temperature of the metals.
disa [49]

Answer:

metal B

temperature flow from high region to low . metal B has more temperature than others

5 0
2 years ago
The angular separation of two stars is 0.1 arcseconds and you photograph them with a telescope that has an angular resolution of
gizmo_the_mogwai [7]

Answer:

Will see them as only one star

Explanation:

Solution:

- The angular resolution of a telescope means the minimum quantity that can be visualized. Since their angular separation ( 0.1 arcseconds ) is smaller than the telescope's angular resolution (1 arcseconds ), your photograph will seem to show only one star rather than two.

7 0
3 years ago
Anyone know the answer to this, would kindly appreciate it
Ipatiy [6.2K]

Answer:

The found value of r is:

r = 94.7

Explanation:

We know that

cosθ = Base / Hypotenuse

θ is the always the angle between base and hypotenuse

In this right angles triangle, the angle θ is given 63°.

Which means that the Base is 43 and the hypotenuse is r

Base = 43

Hypotenuse = r

Substitute θ=63°, Base = 43 and hypotenuse = r in the formula of cosθ mentioned above:

cos 63° = 43/r

Rearrange

r = 43/cos63°

r = 43/0.454

r= 94.7

6 0
3 years ago
Suppose the initial position of an object is zero, the starting velocity is 3 m/s and the final velocity was 10 m/s. The object
forsale [732]
The area of the rectangle plus the area of the triangle under the line .-.
4 0
4 years ago
Read 2 more answers
Problem 5 You are playing a game where you drop a coin into a water tank and try to land it on a target. You often find this gam
Dvinal [7]

Answer:

Option D: 1.5in in front of the target

Explanation:

The object distance is y= 6in.

Because the surface is flat, the radius of curvature is infinity .

The incident index is n_i=\frac{4}{3} and the transmitted index is n_t= 1.

The single interface equation is \frac{n_i}{y}+\frac{n_t}{y^i}=\frac{n_t-n_i}{r}

Substituting the quantities given in the problem,

\frac{\frac{4}{3}}{6in}+\frac{1}{y^i}= 0

The image distance is then y^i=-\frac{18}{4}in =-4.5in

Therefore, the coin falls 1.5in in front of the target

6 0
3 years ago
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