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dem82 [27]
3 years ago
12

If the L-shaped rod has a moment of inertia I=9kgm2, F1=12N, F2=27N, and again F3=0, how long a time t would it take for the obj

ect to move through 45∘ ( π/4 radians)? Assume that as the object starts to move, each force moves with the object so as to retain its initial angle relative to the object. Express the time in seconds to two significant figures.
Physics
1 answer:
blondinia [14]3 years ago
6 0

Answer:

Time, t = 2.80seconds

Explanation:

Calculating net Torque, T

Torque(net)= F2(0.08m) - F1(0.03)

Torque(net) = (27×0.08)-(12×0.03)

Torque(net)= 2.16 - 0.36 =1.8N/m

Pi/4= Torque(net)/ Inertia

3.142/4= 1.8/9 = 0.2rad/s^2=a

Pi/4= 1/2 at^2

3.142/4=1/2×0.2 ×t^2

0.7855= 0.1 t^2

t = sqrt(0.7856/0.1)

t= sqrt(7.855)

t=2.80 seconds

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A child is perched perilously above a 150m ravine. The child has a mass of 45kg. How much
Finger [1]

Answer:

<em>U = 66,150 J</em>

Explanation:

<u>Gravitational Potential Energy</u>

Gravitational potential energy is the energy stored in an object because of its vertical position or height in a gravitational field.

It can be calculated with the equation:

U=m.g.h

Where m is the mass of the object, h is the height with respect to a fixed reference, and g is the acceleration of gravity or 9.8\ m/s^2.

The child of mass m=45 Kg is perched above a h=150 m ravine. His gravitational potential energy is:

U=45~Kg\cdot 9.8\ m/s^2\cdot 150\ m

U = 66,150 J

6 0
3 years ago
A 2060 kg railroad flatcar, which can move with negligible friction, is motionless next to a platform. A 241 kg sumo wrestler ru
vampirchik [111]

Answer

given,

mass of railroad = 2060 Kg

mass of sumo wrestler = 241 Kg

speed = 5.3 m/s

a) using conservation of momentum

     m v = (m + M) V

     241 x 5.3 = (241 + 2060)V

    V = \dfrac{1277.3}{2301}

      V = 0.556 m/s

b) Let v be the relative speed

  Again using conservation of momentum

  241 x 5.3 =241 x (5.3+v)  + 2060 v

  241 x 5.3 =241 x 5.3+241 x v + 2060 v

  2301 v = 0

       v = 0 m/s

c)  the speed of the flatcar if he then turns and run sat 5.3 m/s relative to the flat car opposite his original direction

  241 x 5.3 =241 x (v - 5.3)  + 2060 v

  241 x 5.3 = - 241 x 5.3+241 x v + 2060 v

  2301 v = 2554.6

      v = 1.11 m/s

3 0
4 years ago
20 POINTS TRUE OR FALSE:
romanna [79]
False because the first law of motion is the crash I think I’m in middle school
8 0
3 years ago
1. What is the temperature in Kelvin and Fahrenheit of silver at 51.4oC?1. What is the temperature in Kelvin and Fahrenheit of s
horsena [70]

Answer:

Temperature in Fahrenheit will be 124.52°F and in kelvin 324.4 K

Explanation:

We have given temperature in of silver in degree Celsius as 51.4^{\circ}C

We have to convert this temperature in Fahrenheit and kelvin

For Fahrenheit

Temperature in Fahrenheit   = \frac{9}{5}\times 51.4+32=124.52^{\circ}F

For kelvin

In kelvin = 51.4+273 = 324.4 K

So temperature in Fahrenheit will be 124.52°F and in kelvin 324.4 K

5 0
3 years ago
two identical springs of spring constant 7580 N/m are attached to a block of mass 0.245 kg. What is the frequency of oscillation
ad-work [718]

The frequency of oscillation on the frictionless floor is 28 Hz.

<h3>Frequency of the simple harmonic motion</h3>

The frequency of the oscillation is calculated as follows;

f = (1/2π)(√k/m)

where;

  • k is the spring constant
  • m is mass of the block

f = (1/2π)(√7580/0.245)

f = 28 Hz

Thus, the frequency of oscillation on the frictionless floor is 28 Hz.

Learn more about frequency here: brainly.com/question/10728818

#SPJ1

3 0
2 years ago
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