Answer:
A = L^3 T^-3 , B = L^3 T
Explanation:
Given: volume ( V ) = At^3 + B/t ------ ( 1 )
dimension of volume = L^3
and the Dimension of time = T
back to equation ( 1 )
L^3 = A * T^3 ------- ( 2 )
also L^3 = B/T ------- ( 3 )
from equation ( 2 )
A = L^3 T^-3
from equation ( 3 )
B = L^3 T
<u>The dimensions of the constants A and B </u>
A = L^3 T^-3 , B = L^3 T
Answer:
Explanation:
Remark
In general, these 3rd class levers are very inefficient. Because the force distance is smaller than the load distance, you need to pull upward with more force that the weight of the load. So whatever the load is, the force is going to be much greater.
The distances are always measured to the pivot unless you are asked something specific otherwise.
Givens
F = ?
weight = 6N
Force Distance = F*d = 0.5 m
Weight Distance =W*d1 = 2 m
Formula
F*Fd = W*Wd
Solution
F*0.5 = 6 * 2 Divide by 0.5
F = 12/0.5
F = 24 N upwards
Answer:
The polar coordinate of
is
.
Explanation:
Given a point in rectangular form, that is
, its polar form is defined by:
(1)
Where:
- Norm, measured in meters.
- Direction, measured in sexagesimal degrees.
The norm of the point is determined by Pythagorean Theorem:
(2)
And direction is calculated by following trigonometric relation:
(3)
If we know that
and
, then the components of coordinates in polar form is:


Since
and
, direction is located at 3rd Quadrant. Given that tangent function has a period of 180º, we find direction by using this formula:


The polar coordinate of
is
.
Answer:
200 km/hr
Explanation:
Since he goes 80km per hour, multiply this by 2.5 or two and a half hours.
80 x 2.5 = 200 km/hr.
Explanation:
The given data is as follows.
C =
R =
ohm
C
Q =
Formula to calculate the time is as follows.
0.135 =
= 7.407
t = 4.00 s
Therefore, we can conclude that time after the resistor is connected will the capacitor is 4.0 sec.